hi
I have a problem with calling functions:

<?php
function solution1($var1) {
// some code
}

function solution2($var2) {
// some code
}

function solution3($var3) {
// some code
}

if ($function == 'solution1' or $function == 'solution2' or $function ==
'solution3')
{
$my_solution = $function($var); # this supposed to call one of
"solution" functions, right?
}
?>

suggestions?

thanks.

-afan

Robin Vickery wrote:
> On 19/10/2007, afan pasalic <afan@afan.net> wrote:
>
>> hi
>> I have a problem with calling functions:
>>
>> <?php
>> function solution1($var1) {
>> // some code
>> }
>>
>> function solution2($var2) {
>> // some code
>> }
>>
>> function solution3($var3) {
>> // some code
>> }
>>
>> if ($function == 'solution1' or $function == 'solution2' or $function ==
>> 'solution3')
>> {
>> $my_solution = $function($var); # this supposed to call one of
>> "solution" functions, right?
>> }
>> ?>
>>
>> suggestions?
>>
>
> suggestions for what?
>
> What is your problem? If you set $function to 'solution1' and run your
> code, it will indeed execute solution1().
>
> -robin
>

the problem is that this code doesn't work. and I was asking where is
the problem, or can I do it this way at all.
:-)

-afan

Jay Blanchard wrote:
> [snip]
> <?php
> function solution1($var1) {
> // some code
> }
>
> function solution2($var2) {
> // some code
> }
>
> function solution3($var3) {
> // some code
> }
>
> if ($function == 'solution1' or $function == 'solution2' or $function ==
> 'solution3')
> {
> $my_solution = $function($var); # this supposed to call one of
> "solution" functions, right?
> }
> ?>
> [/snip]
>
> I don't think you can put a function name in a variable and call it like
> $function($var). You'd be better of with a case statement in one
> function and call the proper solution (quick syntax, may need a little
> fixing;
>
> function my_solution($function, $var){
> switch $function{
> case function1:
> ...do stuff...
> break;
> case function1:
>
>
> etc.....
> }
> }
>

that's exactly what I'm doing now. though, I was thinking if it's possible.
:-(

thanks jay

Jay Blanchard wrote:
> [snip]
> [snip]
> <?php
> function solution1($var1) {
> // some code
> }
>
> function solution2($var2) {
> // some code
> }
>
> function solution3($var3) {
> // some code
> }
>
> if ($function == 'solution1' or $function == 'solution2' or $function ==
> 'solution3')
> {
> $my_solution = $function($var); # this supposed to call one of
> "solution" functions, right?
> }
> ?>
> [/snip]
>
> I don't think you can put a function name in a variable and call it like
> $function($var). You'd be better of with a case statement in one
> function and call the proper solution (quick syntax, may need a little
> fixing;
>
> function my_solution($function, $var){
> switch $function{
> case function1:
> ...do stuff...
> break;
> case function1:
>
>
> etc.....
> }
> }
> [/snip]
>
> And call it like this;
>
> my_solution('function1', $var);
>

actually, I did a little bit different:

switch($function)
{
case 'solution1':
solution1($var1);
break;

case 'solution2':
solution2($var2);
break;

case 'solution3':
solution3($var3);
break;
}



;-)

-afan

On 19/10/2007, afan pasalic <afan@afan.net> wrote:
> hi
> I have a problem with calling functions:
>
> <?php
> function solution1($var1) {
> // some code
> }
>
> function solution2($var2) {
> // some code
> }
>
> function solution3($var3) {
> // some code
> }
>
> if ($function == 'solution1' or $function == 'solution2' or $function ==
> 'solution3')
> {
> $my_solution = $function($var); # this supposed to call one of
> "solution" functions, right?
> }
> ?>
>
> suggestions?

suggestions for what?

What is your problem? If you set $function to 'solution1' and run your
code, it will indeed execute solution1().

-robin

2007. 10. 19, péntek keltezéssel 11.15-kor afan pasalic ezt Ãrta:
> hi
> I have a problem with calling functions:
>
> <?php
> function solution1($var1) {
> // some code
> }
>
> function solution2($var2) {
> // some code
> }
>
> function solution3($var3) {
> // some code
> }
>
> if ($function == 'solution1' or $function == 'solution2' or $function ==
> 'solution3')
> {
> $my_solution = $function($var); # this supposed to call one of
> "solution" functions, right?
> }
> ?>

what's wrong with this?

greets
Zoltán Németh

>
> suggestions?
>
> thanks.
>
> -afan
>

[snip]
<?php
function solution1($var1) {
// some code
}

function solution2($var2) {
// some code
}

function solution3($var3) {
// some code
}

if ($function == 'solution1' or $function == 'solution2' or $function ==
'solution3')
{
$my_solution = $function($var); # this supposed to call one of
"solution" functions, right?
}
?>
[/snip]

I don't think you can put a function name in a variable and call it like
$function($var). You'd be better of with a case statement in one
function and call the proper solution (quick syntax, may need a little
fixing;

function my_solution($function, $var){
switch $function{
case function1:
...do stuff...
break;
case function1:


etc.....
}
}

[snip]
[snip]
<?php
function solution1($var1) {
// some code
}

function solution2($var2) {
// some code
}

function solution3($var3) {
// some code
}

if ($function == 'solution1' or $function == 'solution2' or $function ==
'solution3')
{
$my_solution = $function($var); # this supposed to call one of
"solution" functions, right?
}
?>
[/snip]

I don't think you can put a function name in a variable and call it like
$function($var). You'd be better of with a case statement in one
function and call the proper solution (quick syntax, may need a little
fixing;

function my_solution($function, $var){
switch $function{
case function1:
...do stuff...
break;
case function1:


etc.....
}
}
[/snip]

And call it like this;

my_solution('function1', $var);