How to get the script name when sourcing it?
${0} returns '-bash'.

Thanks a lot.

$BASH_SOURCE

troyzeng wrote:
> How to get the script name when sourcing it?
> ${0} returns '-bash'.
>
> Thanks a lot.

On 25 Apr, 11:46, mop2 <mop2bky4mz5tyjwa8ersp7hrg5u...@gmail.com>
wrote:
> $BASH_SOURCE
>
> troyzeng wrote:
> > How to get the script name when sourcing it?
> > ${0} returns '-bash'.
>
> > Thanks a lot.

Thanks. That works for bash and sh.
What about ksh? Thanks.

2008-04-24, 19:57(-07), troyzeng:
> On 25 Apr, 11:46, mop2 <mop2bky4mz5tyjwa8ersp7hrg5u...@gmail.com>
> wrote:
>> $BASH_SOURCE
>>
>> troyzeng wrote:
>> > How to get the script name when sourcing it?
>> > ${0} returns '-bash'.
>>
>> > Thanks a lot.
>
> Thanks. That works for bash and sh.

Only for sh where sh is implemented by bash, so only GNU
systems.

> What about ksh? Thanks.

Depends on the implementation of ksh. In the zsh implementation,
you'll find it in ${(%):-%N} (%N, in prompt expansion is
expanded to the name of the currently sourced script (for PS2),
(%) enables prompt expansion in parameter expansion ${:-default}
is a special form of ${var:-default} which always expands to
"default").

Portably, you could do:

source() {
sourced_script=$1
. "$1"
}

And use "source" instead of ".". And then use $sourced_script.

--
Stéphane

On 25 Apr, 16:42, Stephane CHAZELAS <this.addr...@is.invalid> wrote:
> 2008-04-24, 19:57(-07), troyzeng:
>
> > On 25 Apr, 11:46, mop2 <mop2bky4mz5tyjwa8ersp7hrg5u...@gmail.com>
> > wrote:
> >> $BASH_SOURCE
>
> >> troyzeng wrote:
> >> > How to get the script name when sourcing it?
> >> > ${0} returns '-bash'.
>
> >> > Thanks a lot.
>
> > Thanks. That works for bash and sh.
>
> Only for sh where sh is implemented by bash, so only GNU
> systems.
>
> > What about ksh? Thanks.
>
> Depends on the implementation of ksh. In the zsh implementation,
> you'll find it in ${(%):-%N} (%N, in prompt expansion is
> expanded to the name of the currently sourced script (for PS2),
> (%) enables prompt expansion in parameter expansion ${:-default}
> is a special form of ${var:-default} which always expands to
> "default").
>
> Portably, you could do:
>
> source() {
> sourced_script=$1
> . "$1"
>
> }
>
> And use "source" instead of ".". And then use $sourced_script.
>
> --
> Stéphane

My question really should be: how to get the script name within the
script when the script is meant to be sourced (to setup environment
like a profile)?
E.g., my script is called a.ksh. I want to find out the script name
within a.ksh. If a.ksh is executed, ${0} is the name of the script (or
the first part of the command line); when a.ksh is sourced, what is
equivalent to $[0}?
Troy

2008-04-25, 02:05(-07), troyzeng:
[...]
> My question really should be: how to get the script name within the
> script when the script is meant to be sourced (to setup environment
> like a profile)?
> E.g., my script is called a.ksh. I want to find out the script name
> within a.ksh. If a.ksh is executed, ${0} is the name of the script (or
> the first part of the command line); when a.ksh is sourced, what is
> equivalent to $[0}?
[...]

So I think you can't unless the caller has made it available in
a variable (as in my source() function example) or unless you
assume ksh is implemented with zsh.

--
Stéphane