printf and shell variable

12/11/2007, 23h16

Greetings,

In my script I have to process variables whose values
(happen to be file names) contains the '%' character

Since I have no control over how files are named,
I was wondering if there is a way I can get around
the situation which I am emulating through an example below:

# export filename=Hello%20World

# printf $filename
bash: printf: `W': invalid format character

Thanks,
Farid

12/11/2007, 23h44

Farid Hamjavar wrote:
> Greetings,
>
> In my script I have to process variables whose values
> (happen to be file names) contains the '%' character
>
> Since I have no control over how files are named,
> I was wondering if there is a way I can get around
> the situation which I am emulating through an example below:
>
>
>
> # export filename=Hello%20World
>
> # printf $filename
> bash: printf: `W': invalid format character

Provide a format string for printf...

$ filename="Hello%20World"
$ printf "%s\n" "$filename"'
Hello%20World

Janis

>
>
>
>
> Thanks,
> Farid
>
>
>

12/11/2007, 23h55

On 11/12/2007 5:16 PM, Farid Hamjavar wrote:
> Greetings,
>
> In my script I have to process variables whose values
> (happen to be file names) contains the '%' character
>
> Since I have no control over how files are named,
> I was wondering if there is a way I can get around
> the situation which I am emulating through an example below:
>
>
>
> # export filename=Hello%20World
>
> # printf $filename
> bash: printf: `W': invalid format character

Yes, use printf as the manual page tells you, i.e.:

printf <format> <text>

so in this case you'd do:

printf "%s\n" "$filename"

Regards,

Ed.

12/11/2007, 23h56

In news:Pine.LNX.4.64.0711121611080.17704@chishio.swc p.com,
Farid Hamjavar <hamjavar@unm.edu> wrote:

> In my script I have to process variables whose values
> (happen to be file names) contains the '%' character
>
> Since I have no control over how files are named,
> I was wondering if there is a way I can get around
> the situation which I am emulating through an example below:
>
> # export filename=Hello%20World
> # printf $filename
> bash: printf: `W': invalid format character

Format the output as a string:
printf %s $filename

12/11/2007, 23h16	#1
Farid Hamjavar Messages: n/a Hébergeur:	printf and shell variable Greetings, In my script I have to process variables whose values (happen to be file names) contains the '%' character Since I have no control over how files are named, I was wondering if there is a way I can get around the situation which I am emulating through an example below: # export filename=Hello%20World # printf $filename bash: printf: `W': invalid format character Thanks, Farid

12/11/2007, 23h44	#2
Janis Papanagnou Messages: n/a Hébergeur:	Re: printf and shell variable Farid Hamjavar wrote: > Greetings, > > In my script I have to process variables whose values > (happen to be file names) contains the '%' character > > Since I have no control over how files are named, > I was wondering if there is a way I can get around > the situation which I am emulating through an example below: > > > > # export filename=Hello%20World > > # printf $filename > bash: printf: `W': invalid format character Provide a format string for printf... $ filename="Hello%20World" $ printf "%s\n" "$filename"' Hello%20World Janis > > > > > Thanks, > Farid > > >

12/11/2007, 23h55	#3
Ed Morton Messages: n/a Hébergeur:	Re: printf and shell variable On 11/12/2007 5:16 PM, Farid Hamjavar wrote: > Greetings, > > In my script I have to process variables whose values > (happen to be file names) contains the '%' character > > Since I have no control over how files are named, > I was wondering if there is a way I can get around > the situation which I am emulating through an example below: > > > > # export filename=Hello%20World > > # printf $filename > bash: printf: `W': invalid format character Yes, use printf as the manual page tells you, i.e.: printf <format> <text> so in this case you'd do: printf "%s\n" "$filename" Regards, Ed.

12/11/2007, 23h56	#4
Gretch Messages: n/a Hébergeur:	Re: printf and shell variable In news:Pine.LNX.4.64.0711121611080.17704@chishio.swc p.com, Farid Hamjavar <hamjavar@unm.edu> wrote: > In my script I have to process variables whose values > (happen to be file names) contains the '%' character > > Since I have no control over how files are named, > I was wondering if there is a way I can get around > the situation which I am emulating through an example below: > > # export filename=Hello%20World > # printf $filename > bash: printf: `W': invalid format character Format the output as a string: printf %s $filename

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