Hi,
How to skip one item in a sh shell script?

for x in 1 2 3; do
if [ $x = "2" ]; then
#??? how to skip 2 and proceed to 3?
next ????
fi
done


Thanks
~Andrew Chen

On 2007-07-30, Andrew Chen wrote:
> Hi,
> How to skip one item in a sh shell script?
>
> for x in 1 2 3; do
> if [ $x = "2" ]; then
> #??? how to skip 2 and proceed to 3?
> next ????
> fi
> done

for x in 1 2 3; do
if [ "$x" = 2 ]; then
continue
fi
done


--
Chris F.A. Johnson, author <http://cfaj.freeshell.org/shell/>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence

On Mon, 30 Jul 2007 19:38:32 -0000, Andrew Chen <hangfei@gmail.com>
wrote:

>Hi,
>How to skip one item in a sh shell script?
>
>for x in 1 2 3; do
> if [ $x = "2" ]; then
> #??? how to skip 2 and proceed to 3?
> next ????
> fi
>done
>
>
>Thanks
>~Andrew Chen

You could use negative logic:

for x in 1 2 3
do
[ $x != 2 ] && {
Do Whatever With X
}
done

hi

>Andrew Chen wrote:
> Hi,
> How to skip one item in a sh shell script?
>
> for x in 1 2 3; do
> if [ $x = "2" ]; then
> #??? how to skip 2 and proceed to 3?
> next ????
> fi
> done
>
for x in 1 3; do <whatever>; done


--
good luck

peter