How split the input path into components

30/07/2007, 07h56

Hi All!

I have a simple problem. but its urgent.

I have a variable in shell. say
$PATH'='/p2k/c9.1/IRB/shell/data";

I need to cut this string with dilimeter 'IRB'. So I want the result
as

$str1 ='/p2k/c9.1/IRB/' or '/p2k/c9.1/IRB'
$str2='shell/data' or '/shell/data'

if $str1= '/p2k/c9.1/' also OK for me.

I tried in this way;
echo "p2k/c9.1/IRB/shell/data"|{ IFS="IRB" read a b c; echo $c;}
but I got 'B/shell/data' I don't why 'B' came?

Please me ASSAP.

30/07/2007, 08h11

On 2007-07-30, ramesh.btech@gmail.com wrote:
>
> I have a simple problem. but its urgent.
>
> I have a variable in shell. say
> $PATH'='/p2k/c9.1/IRB/shell/data";

You shouldn't use a variable named PATH; it conflicts with a
standard variable. Let's assume:

path=/p2k/c9.1/IRB/shell/data

> I need to cut this string with dilimeter 'IRB'. So I want the result
> as
>
> $str1 ='/p2k/c9.1/IRB/' or '/p2k/c9.1/IRB'
> $str2='shell/data' or '/shell/data'
>
> if $str1= '/p2k/c9.1/' also OK for me.
>
> I tried in this way;
> echo "p2k/c9.1/IRB/shell/data"|{ IFS="IRB" read a b c; echo $c;}
> but I got 'B/shell/data' I don't why 'B' came?

Use parameter expansion:

str2=${path#*/IRB} ## Or: str2=${path#*/IRB/}
str1=${path%"$str2"}

--
Chris F.A. Johnson, author <http://cfaj.freeshell.org/shell/>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence

30/07/2007, 08h11

On 2007-07-30, ramesh.btech@gmail.com wrote:
>
> I have a simple problem. but its urgent.
>
> I have a variable in shell. say
> $PATH'='/p2k/c9.1/IRB/shell/data";

You shouldn't use a variable named PATH; it conflicts with a
standard variable. Let's assume:

path=/p2k/c9.1/IRB/shell/data

> I need to cut this string with dilimeter 'IRB'. So I want the result
> as
>
> $str1 ='/p2k/c9.1/IRB/' or '/p2k/c9.1/IRB'
> $str2='shell/data' or '/shell/data'
>
> if $str1= '/p2k/c9.1/' also OK for me.
>
> I tried in this way;
> echo "p2k/c9.1/IRB/shell/data"|{ IFS="IRB" read a b c; echo $c;}
> but I got 'B/shell/data' I don't why 'B' came?

Use parameter expansion:

str2=${path#*/IRB} ## Or: str2=${path#*/IRB/}
str1=${path%"$str2"}

--
Chris F.A. Johnson, author <http://cfaj.freeshell.org/shell/>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence

30/07/2007, 07h56	#1
ramesh.btech@gmail.com Messages: n/a Hébergeur:	How split the input path into components Hi All! I have a simple problem. but its urgent. I have a variable in shell. say $PATH'='/p2k/c9.1/IRB/shell/data"; I need to cut this string with dilimeter 'IRB'. So I want the result as $str1 ='/p2k/c9.1/IRB/' or '/p2k/c9.1/IRB' $str2='shell/data' or '/shell/data' if $str1= '/p2k/c9.1/' also OK for me. I tried in this way; echo "p2k/c9.1/IRB/shell/data"\|{ IFS="IRB" read a b c; echo $c;} but I got 'B/shell/data' I don't why 'B' came? Please me ASSAP.

30/07/2007, 08h11	#2
Chris F.A. Johnson Messages: n/a Hébergeur:	Re: How split the input path into components On 2007-07-30, ramesh.btech@gmail.com wrote: > > I have a simple problem. but its urgent. > > I have a variable in shell. say > $PATH'='/p2k/c9.1/IRB/shell/data"; You shouldn't use a variable named PATH; it conflicts with a standard variable. Let's assume: path=/p2k/c9.1/IRB/shell/data > I need to cut this string with dilimeter 'IRB'. So I want the result > as > > $str1 ='/p2k/c9.1/IRB/' or '/p2k/c9.1/IRB' > $str2='shell/data' or '/shell/data' > > if $str1= '/p2k/c9.1/' also OK for me. > > I tried in this way; > echo "p2k/c9.1/IRB/shell/data"\|{ IFS="IRB" read a b c; echo $c;} > but I got 'B/shell/data' I don't why 'B' came? Use parameter expansion: str2=${path#/IRB} ## Or: str2=${path#/IRB/} str1=${path%"$str2"} -- Chris F.A. Johnson, author <http://cfaj.freeshell.org/shell/> Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress) ===== My code in this post, if any, assumes the POSIX locale ===== and is released under the GNU General Public Licence

30/07/2007, 08h11	#3
Chris F.A. Johnson Messages: n/a Hébergeur:	Re: How split the input path into components On 2007-07-30, ramesh.btech@gmail.com wrote: > > I have a simple problem. but its urgent. > > I have a variable in shell. say > $PATH'='/p2k/c9.1/IRB/shell/data"; You shouldn't use a variable named PATH; it conflicts with a standard variable. Let's assume: path=/p2k/c9.1/IRB/shell/data > I need to cut this string with dilimeter 'IRB'. So I want the result > as > > $str1 ='/p2k/c9.1/IRB/' or '/p2k/c9.1/IRB' > $str2='shell/data' or '/shell/data' > > if $str1= '/p2k/c9.1/' also OK for me. > > I tried in this way; > echo "p2k/c9.1/IRB/shell/data"\|{ IFS="IRB" read a b c; echo $c;} > but I got 'B/shell/data' I don't why 'B' came? Use parameter expansion: str2=${path#/IRB} ## Or: str2=${path#/IRB/} str1=${path%"$str2"} -- Chris F.A. Johnson, author <http://cfaj.freeshell.org/shell/> Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress) ===== My code in this post, if any, assumes the POSIX locale ===== and is released under the GNU General Public Licence

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