How to include a carriage return in a variable?

06/12/2006, 21h26

I'd like to open a file called text.txt, to search for "value", and to
change this string to a short paragraph. Here's what I tried but it
didn't work:

sed 's/value/firstline \r secondline \r thirdline/g' text.txt >
tempfile && mv -- tempfile text.txt

The "\r" appears as " r " instead of creating carriage returns. Any
idea?
Thanks in advance,

06/12/2006, 21h34

2006-12-6, 13:26(-08), Charles A. Landemaine:
> I'd like to open a file called text.txt, to search for "value", and to
> change this string to a short paragraph. Here's what I tried but it
> didn't work:
>
> sed 's/value/firstline \r secondline \r thirdline/g' text.txt >
> tempfile && mv -- tempfile text.txt
>
> The "\r" appears as " r " instead of creating carriage returns. Any
> idea?
[...]

Note that carriable return is not the line separator on Unix. On
Unix, it's linefeed also known as newline, ^J, LF, NL, \n, 0x0a,
\012.

sed 's/value/firstline\
secondline\
thirdline/g' text.txt

--
Stéphane

06/12/2006, 22h09

Stephane CHAZELAS wrote:
> Note that carriable return is not the line separator on Unix. On
> Unix, it's linefeed also known as newline, ^J, LF, NL, \n, 0x0a,
> \012.
>
> sed 's/value/firstline\
> secondline\
> thirdline/g' text.txt

Thanks, Stéphane, this did the trick!

Charles.

06/12/2006, 21h26	#1
Charles A. Landemaine Messages: n/a Hébergeur:	How to include a carriage return in a variable? I'd like to open a file called text.txt, to search for "value", and to change this string to a short paragraph. Here's what I tried but it didn't work: sed 's/value/firstline \r secondline \r thirdline/g' text.txt > tempfile && mv -- tempfile text.txt The "\r" appears as " r " instead of creating carriage returns. Any idea? Thanks in advance,

06/12/2006, 21h34	#2
Stephane CHAZELAS Messages: n/a Hébergeur:	Re: How to include a carriage return in a variable? 2006-12-6, 13:26(-08), Charles A. Landemaine: > I'd like to open a file called text.txt, to search for "value", and to > change this string to a short paragraph. Here's what I tried but it > didn't work: > > sed 's/value/firstline \r secondline \r thirdline/g' text.txt > > tempfile && mv -- tempfile text.txt > > The "\r" appears as " r " instead of creating carriage returns. Any > idea? [...] Note that carriable return is not the line separator on Unix. On Unix, it's linefeed also known as newline, ^J, LF, NL, \n, 0x0a, \012. sed 's/value/firstline\ secondline\ thirdline/g' text.txt -- Stéphane

06/12/2006, 22h09	#3
Charles A. Landemaine Messages: n/a Hébergeur:	Re: How to include a carriage return in a variable? Stephane CHAZELAS wrote: > Note that carriable return is not the line separator on Unix. On > Unix, it's linefeed also known as newline, ^J, LF, NL, \n, 0x0a, > \012. > > sed 's/value/firstline\ > secondline\ > thirdline/g' text.txt Thanks, Stéphane, this did the trick! Charles.

Outils de la discussion
Afficher une version imprimable Envoyer un lien vers cette page par email