Excluding an output line

03/12/2006, 06h58

How can I run this command,

repquota -v /home | awk '{if ($3 > $4) print $0 }'

but prevent it outputting lines starting with a #ddddd ie

#11779 -- 8 0 0 2 0 0

It would sure make life easier

TIA

Owen

03/12/2006, 07h28

Owen wrote:
> How can I run this command,
>
> repquota -v /home | awk '{if ($3 > $4) print $0 }'

Try: if ($3 > $4 || substr($0,1,1) != "#")

> but prevent it outputting lines starting with a #ddddd ie
>
> #11779 -- 8 0 0 2 0 0
>
> It would sure make life easier
>
> TIA
>
>
> Owen

03/12/2006, 07h42

RolandRB wrote:
> Owen wrote:
> > How can I run this command,
> >
> > repquota -v /home | awk '{if ($3 > $4) print $0 }'
>
> Try: if ($3 > $4 || substr($0,1,1) != "#")

Nearly, but thanks for the clue, this worked

repquota -v /home | awk '{if (($3 > $4) && (substr($0,1,1) != "#"))
print $0 }'

Thanks

Owen

>
> > but prevent it outputting lines starting with a #ddddd ie
> >
> > #11779 -- 8 0 0 2 0 0
> >
> > It would sure make life easier
> >
> > TIA
> >
> >
> > Owen

03/12/2006, 07h54

Owen wrote:
> RolandRB wrote:
> > Owen wrote:
> > > How can I run this command,
> > >
> > > repquota -v /home | awk '{if ($3 > $4) print $0 }'
> >
> > Try: if ($3 > $4 || substr($0,1,1) != "#")
>
>
> Nearly, but thanks for the clue, this worked
>
> repquota -v /home | awk '{if (($3 > $4) && (substr($0,1,1) != "#"))
> print $0 }'
>
>
> Thanks
>
> Owen

Yes "&&" and not "||" - duh! It was before my morning cup of coffee.

>
> >
> > > but prevent it outputting lines starting with a #ddddd ie
> > >
> > > #11779 -- 8 0 0 2 0 0
> > >
> > > It would sure make life easier
> > >
> > > TIA
> > >
> > >
> > > Owen

03/12/2006, 08h08

Owen wrote:
> RolandRB wrote:
> > Owen wrote:
> > > How can I run this command,
> > >
> > > repquota -v /home | awk '{if ($3 > $4) print $0 }'
> >
> > Try: if ($3 > $4 || substr($0,1,1) != "#")
>
>
> Nearly, but thanks for the clue, this worked
>
> repquota -v /home | awk '{if (($3 > $4) && (substr($0,1,1) != "#"))
> print $0 }'
>
>
> Thanks
>
> Owen

You could have piped it grep to get rid of those lines like this:

repquota -v /home | awk '{if ($3 > $4) print $0 }' | grep -v ^#

....but then you already knew that, didn't you?

03/12/2006, 10h19

2006-12-2, 22:58(-08), Owen:
>
> How can I run this command,
>
> repquota -v /home | awk '{if ($3 > $4) print $0 }'
>
> but prevent it outputting lines starting with a #ddddd ie
>
> #11779 -- 8 0 0 2 0 0
>
> It would sure make life easier
[...]

repquota -v /home |
POSIXLY_CORRECT=1 awk '$3 > $4 && ! /^#[0-9]{5}/'

--
Stéphane

03/12/2006, 10h20

RolandRB wrote:
> Owen wrote:
> > RolandRB wrote:
> > > Owen wrote:
> > > > How can I run this command,
> > > >
> > > > repquota -v /home | awk '{if ($3 > $4) print $0 }'
> > >
> > > Try: if ($3 > $4 || substr($0,1,1) != "#")
> >
> >
> > Nearly, but thanks for the clue, this worked
> >
> > repquota -v /home | awk '{if (($3 > $4) && (substr($0,1,1) != "#"))
> > print $0 }'
> >
> >
> > Thanks
> >
> > Owen
>
> You could have piped it grep to get rid of those lines like this:
>
> repquota -v /home | awk '{if ($3 > $4) print $0 }' | grep -v ^#
>
> ...but then you already knew that, didn't you?

I tried piping it thru a grep --exclude=/something/ . I just looked up
man grep and have no idea why I did that. Time to go to bed!

Thanks again

Owen

03/12/2006, 10h52

"Owen" <xemoth@gmail.com> wrote in message
news:1165129096.825454.209430@79g2000cws.googlegro ups.com...
>
> How can I run this command,
>
> repquota -v /home | awk '{if ($3 > $4) print $0 }'
>
> but prevent it outputting lines starting with a #ddddd ie
>
> #11779 -- 8 0 0 2 0 0

gawk --re-interval '$3>$4&&$1!~/#[0-9]{5}/'

Regards
Dimitre

03/12/2006, 11h21

Owen wrote:
> RolandRB wrote:
> > Owen wrote:
> > > RolandRB wrote:
> > > > Owen wrote:
> > > > > How can I run this command,
> > > > >
> > > > > repquota -v /home | awk '{if ($3 > $4) print $0 }'
> > > >
> > > > Try: if ($3 > $4 || substr($0,1,1) != "#")
> > >
> > >
> > > Nearly, but thanks for the clue, this worked
> > >
> > > repquota -v /home | awk '{if (($3 > $4) && (substr($0,1,1) != "#"))
> > > print $0 }'
> > >
> > >
> > > Thanks
> > >
> > > Owen
> >
> > You could have piped it grep to get rid of those lines like this:
> >
> > repquota -v /home | awk '{if ($3 > $4) print $0 }' | grep -v ^#
> >
> > ...but then you already knew that, didn't you?
>
>
> I tried piping it thru a grep --exclude=/something/ . I just looked up
> man grep and have no idea why I did that. Time to go to bed!
>
> Thanks again

You could also use awk's regular expression filter (or whatever it is
called) with:

awk '/^[^#]/ && $3 > $4'

The above should work, I think.

03/12/2006, 07h28	#2
RolandRB Messages: n/a Hébergeur:	Re: Excluding an output line Owen wrote: > How can I run this command, > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' Try: if ($3 > $4 \|\| substr($0,1,1) != "#") > but prevent it outputting lines starting with a #ddddd ie > > #11779 -- 8 0 0 2 0 0 > > It would sure make life easier > > TIA > > > Owen

03/12/2006, 07h42	#3
Owen Messages: n/a Hébergeur:	Re: Excluding an output line RolandRB wrote: > Owen wrote: > > How can I run this command, > > > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > Try: if ($3 > $4 \|\| substr($0,1,1) != "#") Nearly, but thanks for the clue, this worked repquota -v /home \| awk '{if (($3 > $4) && (substr($0,1,1) != "#")) print $0 }' Thanks Owen > > > but prevent it outputting lines starting with a #ddddd ie > > > > #11779 -- 8 0 0 2 0 0 > > > > It would sure make life easier > > > > TIA > > > > > > Owen

03/12/2006, 07h54	#4
RolandRB Messages: n/a Hébergeur:	Re: Excluding an output line Owen wrote: > RolandRB wrote: > > Owen wrote: > > > How can I run this command, > > > > > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > > > Try: if ($3 > $4 \|\| substr($0,1,1) != "#") > > > Nearly, but thanks for the clue, this worked > > repquota -v /home \| awk '{if (($3 > $4) && (substr($0,1,1) != "#")) > print $0 }' > > > Thanks > > Owen Yes "&&" and not "\|\|" - duh! It was before my morning cup of coffee. > > > > > > but prevent it outputting lines starting with a #ddddd ie > > > > > > #11779 -- 8 0 0 2 0 0 > > > > > > It would sure make life easier > > > > > > TIA > > > > > > > > > Owen

03/12/2006, 08h08	#5
RolandRB Messages: n/a Hébergeur:	Re: Excluding an output line Owen wrote: > RolandRB wrote: > > Owen wrote: > > > How can I run this command, > > > > > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > > > Try: if ($3 > $4 \|\| substr($0,1,1) != "#") > > > Nearly, but thanks for the clue, this worked > > repquota -v /home \| awk '{if (($3 > $4) && (substr($0,1,1) != "#")) > print $0 }' > > > Thanks > > Owen You could have piped it grep to get rid of those lines like this: repquota -v /home \| awk '{if ($3 > $4) print $0 }' \| grep -v ^# ....but then you already knew that, didn't you?

03/12/2006, 10h19	#6
Stephane CHAZELAS Messages: n/a Hébergeur:	Re: Excluding an output line 2006-12-2, 22:58(-08), Owen: > > How can I run this command, > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > but prevent it outputting lines starting with a #ddddd ie > > #11779 -- 8 0 0 2 0 0 > > It would sure make life easier [...] repquota -v /home \| POSIXLY_CORRECT=1 awk '$3 > $4 && ! /^#[0-9]{5}/' -- Stéphane

03/12/2006, 06h58	#1
Owen Messages: n/a Hébergeur:	Excluding an output line How can I run this command, repquota -v /home \| awk '{if ($3 > $4) print $0 }' but prevent it outputting lines starting with a #ddddd ie #11779 -- 8 0 0 2 0 0 It would sure make life easier TIA Owen

03/12/2006, 10h20	#7
Owen Messages: n/a Hébergeur:	Re: Excluding an output line RolandRB wrote: > Owen wrote: > > RolandRB wrote: > > > Owen wrote: > > > > How can I run this command, > > > > > > > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > > > > > Try: if ($3 > $4 \|\| substr($0,1,1) != "#") > > > > > > Nearly, but thanks for the clue, this worked > > > > repquota -v /home \| awk '{if (($3 > $4) && (substr($0,1,1) != "#")) > > print $0 }' > > > > > > Thanks > > > > Owen > > You could have piped it grep to get rid of those lines like this: > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' \| grep -v ^# > > ...but then you already knew that, didn't you? I tried piping it thru a grep --exclude=/something/ . I just looked up man grep and have no idea why I did that. Time to go to bed! Thanks again Owen

03/12/2006, 10h52	#8
Radoulov, Dimitre Messages: n/a Hébergeur:	Re: Excluding an output line "Owen" <xemoth@gmail.com> wrote in message news:1165129096.825454.209430@79g2000cws.googlegro ups.com... > > How can I run this command, > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > but prevent it outputting lines starting with a #ddddd ie > > #11779 -- 8 0 0 2 0 0 gawk --re-interval '$3>$4&&$1!~/#[0-9]{5}/' Regards Dimitre

03/12/2006, 11h21	#9
RolandRB Messages: n/a Hébergeur:	Re: Excluding an output line Owen wrote: > RolandRB wrote: > > Owen wrote: > > > RolandRB wrote: > > > > Owen wrote: > > > > > How can I run this command, > > > > > > > > > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' > > > > > > > > Try: if ($3 > $4 \|\| substr($0,1,1) != "#") > > > > > > > > > Nearly, but thanks for the clue, this worked > > > > > > repquota -v /home \| awk '{if (($3 > $4) && (substr($0,1,1) != "#")) > > > print $0 }' > > > > > > > > > Thanks > > > > > > Owen > > > > You could have piped it grep to get rid of those lines like this: > > > > repquota -v /home \| awk '{if ($3 > $4) print $0 }' \| grep -v ^# > > > > ...but then you already knew that, didn't you? > > > I tried piping it thru a grep --exclude=/something/ . I just looked up > man grep and have no idea why I did that. Time to go to bed! > > Thanks again You could also use awk's regular expression filter (or whatever it is called) with: awk '/^[^#]/ && $3 > $4' The above should work, I think.

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