Hello everyone,
I need your

I have a string the contains a date "20061024"

I wand to convert it to 24/10/2006

Thanks

Rafael

Rafael The Engel wrote:
> Hello everyone,
> I need your
>
> I have a string the contains a date "20061024"
>
> I wand to convert it to 24/10/2006

$ date="20061024"
$ tmp="${date%??}"
$ echo "${date#??????}/${tmp#????}/${tmp%??}"
24/10/2006

Regards,

Ed.

You are the MAN!!!!!!

thanks a lot

Rafael

Rafael The Engel wrote:
> Hello everyone,
> I need your
>
> I have a string the contains a date "20061024"
>
> I wand to convert it to 24/10/2006
>
Maybe you like sed. ;-)

sed
's/\([[:digit:]]\{4\}\)\([[:digit:]]\{2\}\)\([[:digit:]]\{2\}\)/\3\/\2\/\1/'
<<< "20061024"

sed 's/\([0-9]\{4\}\)\([0-9]\{2\}\)\([0-9]\{2\}\)/\3\/\2\/\1/' <<<
"20061024"


> Thanks
>
> Rafael
>

HTH,
--
Stephan Grein, <stephan at stephan minus rockt dot de>
https://stephan-rockt.de
GnuPG-Key-ID: 0xF8C275D4
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Uhm!
<<< "string" works only on GNU Bash imho.
You can use echo "date" | sed ...

Sorry.
--
Stephan Grein, <stephan at stephan minus rockt dot de>
https://stephan-rockt.de
GnuPG-Key-ID: 0xF8C275D4
FingerPrint: 5B6F 134A 189B A24D 342B 0961 8D4B 0230 F8C2 75D4

Stephan Grein wrote:
> Uhm!
> <<< "string" works only on GNU Bash imho.

....and in (newer) ksh93's.

Janis

> You can use echo "date" | sed ...
>
> Sorry.

Janis Papanagnou wrote:
> Stephan Grein wrote:
>
>> Uhm!
>> <<< "string" works only on GNU Bash imho.
>
> ...and in (newer) ksh93's.

....and in zsh.

> Janis
>
>> You can use echo "date" | sed ...
>>
>> Sorry.

> I have a string the contains a date "20061024"
>
> I wand to convert it to 24/10/2006

ksh93/bash

$ var="20061024"

$ echo "${var:0:4}/${var:4:2}/${var:6:2}"
2006/10/24


Regards
Dimitre

>> I have a string the contains a date "20061024"
>>
>> I wand to convert it to 24/10/2006
>
> ksh93/bash
>
> $ var="20061024"
>
> $ echo "${var:0:4}/${var:4:2}/${var:6:2}"
> 2006/10/24

Sorry

echo "${var:6:2}/${var:4:2}/${var:0:4}"
24/10/2006


Regards
Dimitre

Could you please explain the following code in brief words.
Ed Morton wrote:
> Rafael The Engel wrote:
> > Hello everyone,
> > I need your
> >
> > I have a string the contains a date "20061024"
> >
> > I wand to convert it to 24/10/2006
>
> $ date="20061024"
> $ tmp="${date%??}"
> $ echo "${date#??????}/${tmp#????}/${tmp%??}"
> 24/10/2006
>
> Regards,
>
> Ed.

vishu wrote:
> Could you please explain the following code in brief words.
> Ed Morton wrote:
>
>>Rafael The Engel wrote:
>>
>>>Hello everyone,
>>>I need your
>>>
>>>I have a string the contains a date "20061024"
>>>
>>>I wand to convert it to 24/10/2006
>>
>>$ date="20061024"

A string assignment.

>>$ tmp="${date%??}"

Strip the last two characters "24" from string 'date', store the
remainder "200610" in 'tmp'.

>>$ echo "${date#??????}/${tmp#????}/${tmp%??}"

Three parts separated by '/' are printed;
- strip first (#) six characters from 'date' leaving "24"
- strip first (#) four characters from 'tmp' leaving "10"
- strip the last (%) two characters from 'tmp' leaving "2006"

Janis

>>24/10/2006
>>
>>Regards,
>>
>> Ed.
>
>

Stephan Grein wrote:
> Rafael The Engel wrote:
>> Hello everyone,
>> I need your
>>
>> I have a string the contains a date "20061024"
>>
>> I wand to convert it to 24/10/2006
>>
> Maybe you like sed. ;-)
>
> sed
> 's/\([[:digit:]]\{4\}\)\([[:digit:]]\{2\}\)\([[:digit:]]\{2\}\)/\3\/\2\/\1/'
> <<< "20061024"
>
> sed 's/\([0-9]\{4\}\)\([0-9]\{2\}\)\([0-9]\{2\}\)/\3\/\2\/\1/' <<<
> "20061024"
>
>

If you know the format is always YYYYMMHH,
and use a # delimiter:

sed 's#\(....\)\(..\)\(..\)#\3/\2/\1#'

which becomes even good readable as:
group with \( brackets \) into 4, 2, 2 character strings,
then print \3rd, \2nd, \1st bracket with a / in between.


--
Michael Tosch @ hp : com