# NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"

This code I thought would simply copy everything ending in ".csv" to
another directory, but I get the following error:

No such file or directory *.csv

What must I do to ensure copying files over?

Thanx
Phil

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

phillip.s.powell@gmail.com wrote:
> # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
> cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
> cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
>
Try that:
cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
"$csvBackupPath/clientCSV/${file}"; done
cd "$projectDocPath/" && for file in *.csv; do cp -p "$file"
"$csvBackupPath/projectCSV/${file}"; done

> This code I thought would simply copy everything ending in ".csv" to
> another directory, but I get the following error:
>
> No such file or directory *.csv
You got wrong with the * quantifier.
>
> What must I do to ensure copying files over?

try above
>
> Thanx
> Phil
>
np

- --
Stephan 'smg' Grein, <stephan at stephan minus rockt dot de>
https://stephangrein.de
GnuPG-Key-ID: 0xF8C275D4
FingerPrint: 5B6F 134A 189B A24D 342B 0961 8D4B 0230 F8C2 75D4
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Stephan 'smg' Grein wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> phillip.s.powell@gmail.com wrote:
> > # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
> > cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
> > cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
> >
> Try that:
> cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
> "$csvBackupPath/clientCSV/${file}"; done
> cd "$projectDocPath/" && for file in *.csv; do cp -p "$file"
> "$csvBackupPath/projectCSV/${file}"; done
>
> > This code I thought would simply copy everything ending in ".csv" to
> > another directory, but I get the following error:
> >
> > No such file or directory *.csv
> You got wrong with the * quantifier.
> >
> > What must I do to ensure copying files over?
>
> try above
> >
> > Thanx
> > Phil
> >
> np


Could you please explain that? None of it made sense to me, what is
that/??

Phil







>
> - --
> Stephan 'smg' Grein, <stephan at stephan minus rockt dot de>
> https://stephangrein.de
> GnuPG-Key-ID: 0xF8C275D4
> FingerPrint: 5B6F 134A 189B A24D 342B 0961 8D4B 0230 F8C2 75D4
> -----BEGIN PGP SIGNATURE-----
> Version: GnuPG v1.4.5 (GNU/Linux)
>
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> -----END PGP SIGNATURE-----

Stephan 'smg' Grein wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> phillip.s.powell@gmail.com wrote:
> > # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
> > cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
> > cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
> >
> Try that:
> cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
> "$csvBackupPath/clientCSV/${file}"; done
> cd "$projectDocPath/" && for file in *.csv; do cp -p "$file"
> "$csvBackupPath/projectCSV/${file}"; done

you may get into trouble if "$projectDocPath" is not an absolute path.
to keep the current directory info, you may want to use sub-shell with
your commands, like

( cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
"$csvBackupPath/clientCSV/${file}"; done )

Also, using 'find' might save OP some typing:

find "$clientDocPath" -type f -name "*.csv"
-exec cp -p "{}" "$csvBackupPath/clientCSV/" \;

or use find | xargs, find -exec ... + .....

(untested)
Xicheng

On 24 Aug 2006 10:10:52 -0700, phillip.s.powell@gmail.com
<phillip.s.powell@gmail.com> wrote:
>
> Stephan 'smg' Grein wrote:
>> -----BEGIN PGP SIGNED MESSAGE-----
>> Hash: SHA1
>>
>> phillip.s.powell@gmail.com wrote:
>> > # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
>> > cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
>> > cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
>> >
>> Try that:
>> cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
>> "$csvBackupPath/clientCSV/${file}"; done
>> cd "$projectDocPath/" && for file in *.csv; do cp -p "$file"
>> "$csvBackupPath/projectCSV/${file}"; done
>>
>> > This code I thought would simply copy everything ending in ".csv" to
>> > another directory, but I get the following error:
>> >
>> > No such file or directory *.csv
>> You got wrong with the * quantifier.
>> >
>> > What must I do to ensure copying files over?
>>
>> try above
>> >
>> > Thanx
>> > Phil
>> >
>> np
>
>
> Could you please explain that? None of it made sense to me, what is
> that/??
>
> Phil
>
In sh and similar shells, if there is no file matching a wildcard
expression, the wildcard expression is left as is on the command
line. To avoid an error, you can use

if [ -f "$clientDocPath/*.csv" ]; then
cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
fi


--
Truth is the most valuable thing we have -- so let us economize it.
-- Mark Twain

On 2006-08-24, phillip.s.powell@gmail.com wrote:
> # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
> cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
> cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
>
> This code I thought would simply copy everything ending in ".csv" to
> another directory, but I get the following error:
>
> No such file or directory *.csv

Filenames are not expanded inside quotes:

cp -pr "$clientDocPath/"*.csv "$csvBackupPath/clientCSV"
cp -pr "$projectDocPath/"*.csv "$csvBackupPath/projectCSV"

--
Chris F.A. Johnson, author <http://cfaj.freeshell.org>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence

On 2006-08-24, Bill Marcum wrote:
> On 24 Aug 2006 10:10:52 -0700, phillip.s.powell@gmail.com
> <phillip.s.powell@gmail.com> wrote:
>>
>> Stephan 'smg' Grein wrote:
>>> -----BEGIN PGP SIGNED MESSAGE-----
>>> Hash: SHA1
>>>
>>> phillip.s.powell@gmail.com wrote:
>>> > # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
>>> > cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
>>> > cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
>>> >
>>> Try that:
>>> cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
>>> "$csvBackupPath/clientCSV/${file}"; done
>>> cd "$projectDocPath/" && for file in *.csv; do cp -p "$file"
>>> "$csvBackupPath/projectCSV/${file}"; done
>>>
>>> > This code I thought would simply copy everything ending in ".csv" to
>>> > another directory, but I get the following error:
>>> >
>>> > No such file or directory *.csv
>>> You got wrong with the * quantifier.
>>> >
>>> > What must I do to ensure copying files over?
>>>
>>> try above
>>
>> Could you please explain that? None of it made sense to me, what is
>> that/??
>>
> In sh and similar shells, if there is no file matching a wildcard
> expression, the wildcard expression is left as is on the command
> line. To avoid an error, you can use
>
> if [ -f "$clientDocPath/*.csv" ]; then

That doesn't work, because the wildcard will not be expanded.

> cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
> fi
>
>


--
Chris F.A. Johnson, author <http://cfaj.freeshell.org>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence