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| comp.protocols.tcp-ip TCP and IP network protocols. |
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LinkBack | Outils de la discussion |
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#1 |
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Hébergeur: |
can any1 me plz
i've got the following Host Address is 164.14.83.19 Supernet is \16 Subnet mask is 255.255.255.0 i need to get the network address along with the subnet address, i've done the following to work this out but think i may have worked it out crossed the answers some how, can some1 plz tell me if i'm on the right patch or if i've messed up network address = Host_ad + Subnet mask 10100100.00001110.01010011.00010011 (host_address) 11111111.11111111.11111111.00000000 (subnet_mask) ----------------------------------------------- 10100100.00001110.01010011.00000000 (network address) = 164.14.83.0 Subnet Address = Net_ad + supernet 10100100.00001110.01010011.00000000 (network Address) 11111111.11111111.00000000.00000000 (Supernet) ----------------------------------------------- 10100100.00001110.00000000.00000000 (subnet address) = 164.14.0.0 thanks in advance. ALi |
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#2 |
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ALi wrote:
> can any1 me plz > > i've got the following > Host Address is 164.14.83.19 Supernet is \16 Subnet mask is 255.255.255.0 imht (in my humble terminology) 164.14.83.19/24 translates to: network id: 164.14.83.0 host id: .19 subnet mask: 255.255.255.0 > > network address = Host_ad + Subnet mask imht ip address = network id + host id > > 10100100.00001110.01010011.00010011 (host_address) > 11111111.11111111.11111111.00000000 (subnet_mask) > ----------------------------------------------- > 10100100.00001110.01010011.00000000 (network address) = 164.14.83.0 ok > > Subnet Address = Net_ad + supernet > > 10100100.00001110.01010011.00000000 (network Address) > 11111111.11111111.00000000.00000000 (Supernet) *SUPERNET MASK* > ----------------------------------------------- > 10100100.00001110.00000000.00000000 (subnet address) = 164.14.0.0 imht subnet network address + supernet mask = supernet network address hope this s... cheers, paul -- blog http://cobbaut.blogspot.com free linux book http://cobbaut.be/lt/ |
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#3 |
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Hébergeur: |
Paul Cobbaut wrote:
> ALi wrote: >> can any1 me plz >> >> i've got the following >> Host Address is 164.14.83.19 Supernet is \16 Subnet mask is 255.255.255.0 > > imht (in my humble terminology) 164.14.83.19/24 translates to: > network id: 164.14.83.0 > host id: .19 > subnet mask: 255.255.255.0 > > > >> >> network address = Host_ad + Subnet mask > > imht ip address = network id + host id > >> >> 10100100.00001110.01010011.00010011 (host_address) >> 11111111.11111111.11111111.00000000 (subnet_mask) >> ----------------------------------------------- >> 10100100.00001110.01010011.00000000 (network address) = 164.14.83.0 > > ok > >> >> Subnet Address = Net_ad + supernet >> >> 10100100.00001110.01010011.00000000 (network Address) >> 11111111.11111111.00000000.00000000 (Supernet) *SUPERNET MASK* >> ----------------------------------------------- >> 10100100.00001110.00000000.00000000 (subnet address) = 164.14.0.0 > > imht subnet network address + supernet mask = supernet network address > > hope this s... > > cheers, > paul > supernet ? not nooit van gehoord |
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#4 |
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goarilla wrote:
> supernet ? not nooit van gehoord Stel : je hebt in je corporate LAN 800 pc's, dus je hebt 800 ip's nodig. Je kan dit bereiken met 4 class C ranges (/24)... In een tekening: router met netwerk ---- 4 class C ---- corp LAN subnets Maar om de routing tables te beperken kan je aan de netwerkkant van de router een /22 gebruiken, en aan de corp LAN kant die vier class C subnets. De /22 is dan het supernet van die vier /24. groetjes, paul -- blog http://cobbaut.blogspot.com free linux book http://cobbaut.be/lt/ |
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