I'd like to do this:

function makeAnArray(){
$array = array('one'=>'1','two'=array('more than one'=>'dimension'));

return $array;
}

$a = makeAnArray();

// $a is ('one'=>'1','two'=array('more than one'=>'dimension'))

But with the right syntax. How do I do this?

(in perl I'd return a reference and then do a type conversion)

Jeff

Jeff wrote:

> $array = array('one'=>'1','two'=array('more than one'=>'dimension'));

$array = array('one'=>'1','two'=>array('more than one'=>'dimension'));


--
----------------------------------
Iván Sánchez Ortega -ivansanchez-algarroba-escomposlinux-punto-org-

A bus station is where buses stop. A train station is where trains stop. On
my desk, there is a workstation...

Iván Sánchez Ortega wrote:
> Jeff wrote:
>
>> $array = array('one'=>'1','two'=array('more than one'=>'dimension'));
>
> $array = array('one'=>'1','two'=>array('more than one'=>'dimension'));
>
>
Yes, a typo. The actual code though is drawing from an unserialized
file, so I know the syntax php generated is corrected is correct. I also
checked the array just before it got returned and it looked fine.

Are you saying that I can return an array that way?

Jeff

On Jun 20, 4:12pm, Jeff <jeff@spam_me_not.com> wrote:
> Iván Sánchez Ortega wrote:
> > Jeff wrote:
>
> >> $array = array('one'=>'1','two'=array('more than one'=>'dimension'));
>
> > $array = array('one'=>'1','two'=>array('more than one'=>'dimension'));
>
> Yes, a typo. The actual code though is drawing from an unserialized
> file, so I know the syntax php generated is corrected is correct. I also
> checked the array just before it got returned and it looked fine.
>
> Are you saying that I can return an array that way?

Yes, didn't you think of trying it?

I find it a lot quicker to try simple things like this out instead of
writing a post to a forum such as this.

Jeff schreef:
> Iván Sánchez Ortega wrote:
>> Jeff wrote:
>>
>>> $array = array('one'=>'1','two'=array('more than one'=>'dimension'));
>>
>> $array = array('one'=>'1','two'=>array('more than one'=>'dimension'));
>>
>>
> Yes, a typo. The actual code though is drawing from an unserialized
> file, so I know the syntax php generated is corrected is correct. I also
> checked the array just before it got returned and it looked fine.
>
> Are you saying that I can return an array that way?
>
> Jeff

Yes,

$myArr = array (
1 => 12,
50 => "hello fifty",
"IamAssoc" => array(23,45,77),
"meToo" => array("one" => 1, "two" => 2)
)

is perfectly fine.

Regards,
Erwin Moller

Captain Paralytic wrote:
> On Jun 20, 4:12 pm, Jeff <jeff@spam_me_not.com> wrote:

My apologies...

>> Iván Sánchez Ortega wrote:
>>> Jeff wrote:
>>>> $array = array('one'=>'1','two'=array('more than one'=>'dimension'));
>>> $array = array('one'=>'1','two'=>array('more than one'=>'dimension'));
>> Yes, a typo. The actual code though is drawing from an unserialized
>> file, so I know the syntax php generated is corrected is correct. I also
>> checked the array just before it got returned and it looked fine.
>>
>> Are you saying that I can return an array that way?
>
> Yes, didn't you think of trying it?

I tried this in a function in a class, and sprinkled in some echos to
track the data to see where the problem was.

When I try the very same script now, it works. Perhaps I made some
other mistake... Unfortunately, it's not the craziest thing (not
programming though) that's happened today!

Jeff
>
> I find it a lot quicker to try simple things like this out instead of
> writing a post to a forum such as this.
>