I am using PHP with the JSON extension function json_decode.

I have a JSON with a member named "1" (ie) { "1":"somedata" }

Trying to access this via the -> operator doesn't work, nor does
["1"].

Putting the JSON into a foreach loop DOES access the member:

foreach($json as $key=>$value) {
echo("$key<br />");
}
//outputs '1'

Is this an error on my part, an oversight in the PHP JSON
implementation, or something else? Why can foreach grab the members,
but I can't access them?

Thanks for your time!

Tyler

On Tue, 22 Apr 2008 20:32:28 +0200, Logos <tyler.style@gmail.com> wrote:

> I am using PHP with the JSON extension function json_decode.
>
> I have a JSON with a member named "1" (ie) { "1":"somedata" }
>
> Trying to access this via the -> operator doesn't work, nor does
> ["1"].
>
> Putting the JSON into a foreach loop DOES access the member:
>
> foreach($json as $key=>$value) {
> echo("$key<br />");
> }
> //outputs '1'
>
> Is this an error on my part, an oversight in the PHP JSON
> implementation, or something else? Why can foreach grab the members,
> but I can't access them?


The problem is that while json_decode is able to extract it:
object(stdClass)#1 (1) {
["1"]=>
string(8) "somedata"
}

"1" is not a valid property name to use directly.

Workarounds:
Option 1, suitable for single known variable:
<?php
$var = json_decode('{ "1":"somedata" }');
$name = '1';
echo $var->$name;
?>

Option 2, suited for more generic processing:
<?php
function json_object_to_named_array($var){
if(!is_object($var)){
trigger_error('No object given');
return;
}
$return = get_object_vars($var);
foreach($return as &$value){
if(is_object($value)) $value = json_object_to_named_array($value);
}
return $return;
}
$test = array('foo' => 'bar','foz' => array('fox' => 'bax'));
$json = json_encode($test);
var_dump($json);
$var = json_decode($json);
var_dump($var);
$var = json_object_to_named_array($var);
var_dump($var);
?>
Output:
string(33) "{"foo":"bar","foz":{"fox":"bax"}}"
object(stdClass)#1 (2) {
["foo"]=>
string(3) "bar"
["foz"]=>
object(stdClass)#2 (1) {
["fox"]=>
string(3) "bax"
}
}
array(2) {
["foo"]=>
string(3) "bar"
["foz"]=>
array(1) {
["fox"]=>
string(3) "bax"
}
}
--
Rik Wasmus

On Apr 22, 3:14 pm, "Rik Wasmus" <luiheidsgoe...@hotmail.com> wrote:
> On Tue, 22 Apr 2008 20:32:28 +0200, Logos <tyler.st...@gmail.com> wrote:
> > I am using PHP with the JSON extension function json_decode.
>
> > I have a JSON with a member named "1" (ie) { "1":"somedata" }
>
> > Trying to access this via the -> operator doesn't work, nor does
> > ["1"].
>
> > Putting the JSON into a foreach loop DOES access the member:
>
> > foreach($json as $key=>$value) {
> > echo("$key<br />");
> > }
> > //outputs '1'
>
> > Is this an error on my part, an oversight in the PHP JSON
> > implementation, or something else? Why can foreach grab the members,
> > but I can't access them?
>
> The problem is that while json_decode is able to extract it:
> object(stdClass)#1 (1) {
> ["1"]=>
> string(8) "somedata"
>
> }
>
> "1" is not a valid property name to use directly.
>
> Workarounds:
> Option 1, suitable for single known variable:
> <?php
> $var = json_decode('{ "1":"somedata" }');
> $name = '1';
> echo $var->$name;
> ?>
>
> Option 2, suited for more generic processing:
> <?php
> function json_object_to_named_array($var){
> if(!is_object($var)){
> trigger_error('No object given');
> return;
> }
> $return = get_object_vars($var);
> foreach($return as &$value){
> if(is_object($value)) $value = json_object_to_named_array($value);
> }
> return $return;}
>
> $test = array('foo' => 'bar','foz' => array('fox' => 'bax'));
> $json = json_encode($test);
> var_dump($json);
> $var = json_decode($json);
> var_dump($var);
> $var = json_object_to_named_array($var);
> var_dump($var);
> ?>
> Output:
> string(33) "{"foo":"bar","foz":{"fox":"bax"}}"
> object(stdClass)#1 (2) {
> ["foo"]=>
> string(3) "bar"
> ["foz"]=>
> object(stdClass)#2 (1) {
> ["fox"]=>
> string(3) "bax"
> }}
>
> array(2) {
> ["foo"]=>
> string(3) "bar"
> ["foz"]=>
> array(1) {
> ["fox"]=>
> string(3) "bax"
> }}
>
> --
> Rik Wasmus

Ah, I thought it might be something like that then. The JSON notation
is perfectly fine, but PHP's grammar won't let me directly access the
incompatible JSON format. I shall just have to live with it then.

Thanks!

Tyler

Logos wrote:

> Ah, I thought it might be something like that then. The JSON notation
> is perfectly fine, but PHP's grammar won't let me directly access the
> incompatible JSON format. I shall just have to live with it then.



Try echo $var->{1};

On Apr 23, 6:18 pm, Alexey Kulentsov <a...@inbox.ru> wrote:
> Logos wrote:
> > Ah, I thought it might be something like that then. The JSON notation
> > is perfectly fine, but PHP's grammar won't let me directly access the
> > incompatible JSON format. I shall just have to live with it then.
>
>
>
> Try echo $var->{1};

YOU, sirrah, are my HERO! Thank you much much much!!!



Tyler

Logos wrote:
> I am using PHP with the JSON extension function json_decode.
>
> I have a JSON with a member named "1" (ie) { "1":"somedata" }
>
> Trying to access this via the -> operator doesn't work, nor does
> ["1"].

Looks like you're already on your way, but just FYI, the json_decode
function takes an optional second argument that will, if true, cause
objects to be returned as associative arrays instead. Then, the usual
array notation (["1"]) should work.

Dave

On Wed, 30 Apr 2008 03:39:16 +0200, Dave Benjamin
<ramen@lackingtalent.com> wrote:

> Logos wrote:
>> I am using PHP with the JSON extension function json_decode.
>> I have a JSON with a member named "1" (ie) { "1":"somedata" }
>> Trying to access this via the -> operator doesn't work, nor does
>> ["1"].
>
> Looks like you're already on your way, but just FYI, the json_decode
> function takes an optional second argument that will, if true, cause
> objects to be returned as associative arrays instead. Then, the usual
> array notation (["1"]) should work.

D'OH! Going through all that trouble writing a recursive function...
--
Rik Wasmus

On Apr 29, 6:39 pm, Dave Benjamin <ra...@lackingtalent.com> wrote:
> Logos wrote:
> > I am using PHP with the JSON extension function json_decode.
>
> > I have a JSON with a member named "1" (ie) { "1":"somedata" }
>
> > Trying to access this via the -> operator doesn't work, nor does
> > ["1"].
>
> Looks like you're already on your way, but just FYI, the json_decode
> function takes an optional second argument that will, if true, cause
> objects to be returned as associative arrays instead. Then, the usual
> array notation (["1"]) should work.
>
> Dave

Keen - I may try that too. Good to know for future reference, in any
event!

Tyler