hello group,

is it possible to get the size of iterated object:
"sizeof(typename iterator_traits<InputIterator>::value_type);"

and NOT using dereferencing
sizeof(*theIterator); ?

thanks & hand, chris

On Jun 6, 11:17 am, Chris Forone <4...@gmx.at> wrote:

> is it possible to get the size of iterated object:
> "sizeof(typename iterator_traits<InputIterator>::value_type);"

> and NOT using dereferencing
> sizeof(*theIterator); ?

Yes, but it doesn't matter, since the argument of a sizeof
operator is never evaluated (except by the compiler, to
determine its type).

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Chris Forone a écrit :
> is it possible to get the size of iterated object:
> "sizeof(typename iterator_traits<InputIterator>::value_type);"

Looks good to me.

> and NOT using dereferencing
> sizeof(*theIterator); ?

IMO nothing wrong with that since the deferencing will never occur but
the iterator_traits<>::value type is fine.

--
Michael

Michael DOUBEZ schrieb:
> Chris Forone a écrit :
>> is it possible to get the size of iterated object:
>> "sizeof(typename iterator_traits<InputIterator>::value_type);"
>
> Looks good to me.
>
>> and NOT using dereferencing
>> sizeof(*theIterator); ?
>
> IMO nothing wrong with that since the deferencing will never occur but
> the iterator_traits<>::value type is fine.
>

Ah, thanks. Its only because of the dereferencing. I forgot that
sizeof() ist compiler-related...

:-) cheers, chris