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#1 |
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I'm implementing a garbage collector in C++ for a fun new language
(don't ask), and I've found that it spends a good amount of time calling "finalize" on objects that are freed/not relocated. The default implementation does nothing and always will, and most types won't need to override it. It'd be nice if I could test for overrides, but the obvious thing doesn't work: class Object { // ... virtual void finalize() { } // ... }; // In the collector: Object* pobj = <stuff>; if (&pobj->finalize != &hv_Object::finalize) pobj->finalize(); // GCC: // ISO C++ forbids taking the address of a bound member function // to form a pointer to member function. Say '&hv_Object::finalize' I'd love to do what it says, but I don't know the type of the object. Is there an easy way to make this same test? I want to avoid RTTI and compiler-specific language extensions, and also make it externally transparent. Neil |
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#2 |
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On Dec 27, 5:17 pm, lord trousers <neil.toro...@gmail.com> wrote:
> I'm implementing a garbage collector in C++ for a fun new language > (don't ask), and I've found that it spends a good amount of time > calling "finalize" on objects that are freed/not relocated. The > default implementation does nothing and always will, and most types > won't need to override it. It'd be nice if I could test for overrides, > but the obvious thing doesn't work: > > class Object { > // ... > virtual void finalize() { } > // ... > }; > > // In the collector: > Object* pobj = <stuff>; > if (&pobj->finalize != &hv_Object::finalize) > pobj->finalize(); > > // GCC: > // ISO C++ forbids taking the address of a bound member function > // to form a pointer to member function. Say > '&hv_Object::finalize' > > I'd love to do what it says, but I don't know the type of the object. > Is there an easy way to make this same test? I want to avoid RTTI and > compiler-specific language extensions, and also make it externally > transparent. > > Neil Funny you should post this a few minutes before me... I'm waiting for the same answer. Let me know if you figure anything out? |
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#3 |
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On 2007-12-28 02:17, lord trousers wrote:
> I'm implementing a garbage collector in C++ for a fun new language > (don't ask), and I've found that it spends a good amount of time > calling "finalize" on objects that are freed/not relocated. The > default implementation does nothing and always will, and most types > won't need to override it. It'd be nice if I could test for overrides, > but the obvious thing doesn't work: > > class Object { > // ... > virtual void finalize() { } > // ... > }; > > // In the collector: > Object* pobj = <stuff>; > if (&pobj->finalize != &hv_Object::finalize) > pobj->finalize(); > > // GCC: > // ISO C++ forbids taking the address of a bound member function > // to form a pointer to member function. Say > '&hv_Object::finalize' > > I'd love to do what it says, but I don't know the type of the object. > Is there an easy way to make this same test? I want to avoid RTTI and > compiler-specific language extensions, and also make it externally > transparent. I do not think you can do that in C++, and there are two reasons for that: the language was designed to hide this kind of stuff from the users, and this sounds like implementation specific territory, so even if you find something that seems to work it might not on another compiler or in the next version of your current. You could use templates to get to know the actual type of the object, but that seems undesirable, and I am not sure even that would work. If you could get the member function pointer for the object it might quite possibly be just an index into the vtable, and what you really want to compare is the values in the entries those indexes points to. But since there is no way in C++ to access the vtables you can not do that either. #include <iostream> struct B { virtual void bar() { } }; struct D1 : public B { virtual void bar() { } }; struct D2 : public B { virtual void bar() { } }; int main() { std::cout << &D1::bar << std::endl; std::cout << &D2::bar << std::endl; } -- Erik Wikström |
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#4 |
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lord trousers <neil.toronto@gmail.com> wrote in news:9100a745-2328-479a-
ae02-d2d445a7da5d@e10g2000prf.googlegroups.com: > I'm implementing a garbage collector in C++ for a fun new language > (don't ask), and I've found that it spends a good amount of time > calling "finalize" on objects that are freed/not relocated. The Are you sure the "if" check would cost less than a virtual function call? If yes, then AFAIK what you want can't be done in the language. I guess you could do it non-portably for each platform/implementation you support. If you only have single inheritance, then it should be relatively simple: the vtable pointer is usually in the beginning of Object, with the knowledge about which vtable slot holds your finalize() function pointer you could be able to compare the pointers. However, I strongly suggest to avoid this path; if the virtual finalize() call is costing too much there is probably something wrong in the overall design, maybe an attempt to handle each integer in an array as a separate object? HTH Paavo > default implementation does nothing and always will, and most types > won't need to override it. It'd be nice if I could test for overrides, > but the obvious thing doesn't work: > > class Object { > // ... > virtual void finalize() { } > // ... > }; > > // In the collector: > Object* pobj = <stuff>; > if (&pobj->finalize != &hv_Object::finalize) > pobj->finalize(); > > // GCC: > // ISO C++ forbids taking the address of a bound member function > // to form a pointer to member function. Say > '&hv_Object::finalize' > > I'd love to do what it says, but I don't know the type of the object. > Is there an easy way to make this same test? I want to avoid RTTI and > compiler-specific language extensions, and also make it externally > transparent. > > Neil |
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#5 |
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On Dec 28 2007, 2:17 am, lord trousers <neil.toro...@gmail.com> wrote:
> I'm implementing a garbage collector in C++ for a fun new > language (don't ask), and I've found that it spends a good > amount of time calling "finalize" on objects that are > freed/not relocated. The default implementation does nothing > and always will, and most types won't need to override it. > It'd be nice if I could test for overrides, but the obvious > thing doesn't work: > class Object { > // ... > virtual void finalize() { } > // ... > }; > // In the collector: > Object* pobj = <stuff>; > if (&pobj->finalize != &hv_Object::finalize) > pobj->finalize(); > // GCC: > // ISO C++ forbids taking the address of a bound member function > // to form a pointer to member function. Say > '&hv_Object::finalize' > I'd love to do what it says, but I don't know the type of the > object. Is there an easy way to make this same test? I want > to avoid RTTI and compiler-specific language extensions, and > also make it externally transparent. Let me see if I understand: you want to avoid RTTI, but you want RTTI. As soon as you try to find out something about the dynamic type, you need RTTI---generally, a virtual function is cheaper (in runtime) than anything else. With regards to finalization with garbage collection, the usual solution is to require explicit registration. This means a (very slight) amount of extra work for the programmer who needs finalization (but such cases are rare), but also means that you don't have to derive everything from a common base---garbage collection can also work for arrays of char, or what have you. (This is how the Boehm collector works, but of course, it also works with C, where virtual functions aren't an option.) -- James Kanze (GABI Software) mailto:james.kanze@gmail.com Conseils en informatique orient�e objet/ Beratung in objektorientierter Datenverarbeitung 9 place S�mard, 78210 St.-Cyr-l'�cole, France, +33 (0)1 30 23 00 34 |
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