char *a="nnnnnnn fgjfjgjf";
char *b="ABC jjjjjjjjjhhhh";

to swap these two string......
this swap fn is working

template<class T>
void Swap( const T *&a,const T *&b)//no need to write const
{
T *temp;
temp=a;

a=b;

b=temp;


}



but to swap


char a[]="nhfhdhfhh fgjfjgjf";
char b[]="ABC jjjjjjjjjhhhh";

these char array its not.
why?
how a[] and b[] can be swapped?
give effficient soln.
don't use swap fn of string library(string1.swap(string2))



Thanx in advance

NK wrote:
> char *a="nnnnnnn fgjfjgjf";
> char *b="ABC jjjjjjjjjhhhh";
>
> to swap these two string......
> this swap fn is working
>
> template<class T>
> void Swap( const T *&a,const T *&b)//no need to write const
> {
> T *temp;
> temp=a;
>
> a=b;
>
> b=temp;
>
>
> }
>
>
>
> but to swap
>
>
> char a[]="nhfhdhfhh fgjfjgjf";
> char b[]="ABC jjjjjjjjjhhhh";
>
> these char array its not.
> why?
> how a[] and b[] can be swapped?
> give effficient soln.
> don't use swap fn of string library(string1.swap(string2))
>
>

Here you go:

http://www.parashift.com/c++-faq-lit...t.html#faq-5.2

On Dec 26, 11:33 pm, NK <nagendra...@gmail.com> wrote:
> char *a="nnnnnnn fgjfjgjf";
> char *b="ABC jjjjjjjjjhhhh";
>
> to swap these two string......
> this swap fn is working
>
> template<class T>
> void Swap( const T *&a,const T *&b)//no need to write const
> {
> T *temp;
> temp=a;
>
> a=b;
>
> b=temp;
>
> }
>
> but to swap
>
> char a[]="nhfhdhfhh fgjfjgjf";
> char b[]="ABC jjjjjjjjjhhhh";
>
> these char array its not.
> why?
> how a[] and b[] can be swapped?
> give effficient soln.
> don't use swap fn of string library(string1.swap(string2))
>
> Thanx in advance

swap function could also check if both the reference are pointing to
same variable or not...

On 26 Dec, 18:33, NK <nagendra...@gmail.com> wrote:
> char *a="nnnnnnn fgjfjgjf";
> char *b="ABC jjjjjjjjjhhhh";
>
> to swap these two string......
> this swap fn is working
>
> template<class T>
> void Swap( const T *&a,const T *&b)//no need to write const
> {
> T *temp;
> temp=a;
>
> a=b;
>
> b=temp;
>
> }
>
> but to swap
>
> char a[]="nhfhdhfhh fgjfjgjf";
> char b[]="ABC jjjjjjjjjhhhh";
>
> these char array its not.
> why?
> how a[] and b[] can be swapped?
> give effficient soln.
> don't use swap fn of string library(string1.swap(string2))
>
> Thanx in advance

Obviously homework, but it's Christmas ...

You can't do this directly - arrays are not assignable.
You could do a character-by-character swap, but then
what if the arrays are of different lengths?

But all of this is academic, you can achieve what you
need like this:

char a[]="nhfhdhfhh fgjfjgjf";
char b[]="ABC jjjjjjjjjhhhh";

char* ap = a;
char* bp = b;

// use ap for a, bp for b

std::swap(ap, bp);

// ap now points to b[], bp to a[]