Hello all,

When I am using array in structure to read a pedigree, I can simply
call an index to see how old is the dad of individual 'i':

Individual[ individual[i].dad_id ].Age

The above example is in a coded pedigree (pedigree starts from
individual '0').

I am wondering how I can do the same as above when I am using the
linked list.

Thanks,
MJ

In article <3a727575-d6c7-47a9-a1c6-e84236b9b466@j78g2000hsd.googlegroups.com>,
MJK <jafarikia@gmail.com> wrote:

>When I am using array in structure to read a pedigree, I can simply
>call an index to see how old is the dad of individual 'i':

>Individual[ individual[i].dad_id ].Age

>The above example is in a coded pedigree (pedigree starts from
>individual '0').

>I am wondering how I can do the same as above when I am using the
>linked list.

If you transform individual into a linked list instead of an
array, then NO, C does not provide any operations to traverse
from the head of a list to the i'th node. On the other hand, you
can easily write your own routine that returns a pointer to
the i'th node, and then use:

find_ith( individual, find_ith( individual, i)->dad_id )->Age
--
'Roberson' is my family name; my given name is 'Walter'.