I don't understand why this expression doesn't work:

$var= '$_POST';

$name= ${$var}[name];


the ${$var}[name] expression wont return the same expression of
$_POST[name].
why does it happens, and how can i solve it?

thanks

On Sep 15, 10:32 am, Gandalf <goldn...@gmail.com> wrote:
> I don't understand why this expression doesn't work:
>
> $var= '$_POST';
>
> $name= ${$var}[name];
>
> the ${$var}[name] expression wont return the same expression of
> $_POST[name].
> why does it happens, and how can i solve it?
>
> thanks

i meant to write $var ='_POST',
and the that ${$var}[name] wont return the same value as $_POST[name]

Gandalf wrote:
> On Sep 15, 10:32 am, Gandalf <goldn...@gmail.com> wrote:
>> I don't understand why this expression doesn't work:
>>
>> $var= '$_POST';
>>
>> $name= ${$var}[name];
>>
>> the ${$var}[name] expression wont return the same expression of
>> $_POST[name].
>> why does it happens, and how can i solve it?
>>
>> thanks
>
> i meant to write $var ='_POST',
> and the that ${$var}[name] wont return the same value as $_POST[name]
>

hi

this should work as expected. Care to post more code?

--
gosha bine

extended php parser ~ http://code.google.com/p/pihipi
blok ~ http://www.tagarga.com/blok

On Sep 15, 11:07 am, gosha bine <stereof...@gmail.com> wrote:
> Gandalf wrote:
> > On Sep 15, 10:32 am, Gandalf <goldn...@gmail.com> wrote:
> >> I don't understand why this expression doesn't work:
>
> >> $var= '$_POST';
>
> >> $name= ${$var}[name];
>
> >> the ${$var}[name] expression wont return the same expression of
> >> $_POST[name].
> >> why does it happens, and how can i solve it?
>
> >> thanks
>
> > i meant to write $var ='_POST',
> > and the that ${$var}[name] wont return the same value as $_POST[name]
>
> hi
>
> this should work as expected. Care to post more code?
>
> --
> gosha bine
>
> extended php parser ~http://code.google.com/p/pihipi
> blok ~http://www.tagarga.com/blok

$var gets the value '_POST'
function create_par($var){
global $_, $_POST, $active;

if(${$var}[no_win_from]!=0 || ${$var}[no_win_to]!=${$var}[games])
$active[0]="no_win"; else die(${$var}[games]);
if(${$var}[out_win_from]!=0 || ${$var}[out_win_to]!=${$var}[games])
$active[1]="out_win";

if(${$var}[yedaActive_2]=="true"){
if(${$var}[range_yeda1_from]!=0 || ${$var}[range_yeda1_to]!=${$var}
[games])$active[2]="range_yeda1";
}
if(${$var}[yedaActive_3]=="true"){
if(${$var}[range_yeda2_from]!=0 || ${$var}[range_yeda2_to]!=${$var}
[games]) $active[3]="range_yeda2";
}
if(${$var}[home_win_from]!=0 || ${$var}[home_win_to]!=${$var}[games])
$active[4]="home_win";
}

..oO(Gandalf)

>$var gets the value '_POST'
>function create_par($var){
> global $_, $_POST, $active;

$_, $_POST etc. are always available, no need to use 'global' on
them. But:

| Please note that variable variables cannot be used with PHP's
| Superglobal arrays within functions or class methods.

Micha

Michael Fesser wrote:

> | Please note that variable variables cannot be used with PHP's
> | Superglobal arrays within functions or class methods.

I read that, and re-read it, and re-read it... and I can't figure out
what it means. Can you re-phrase it?

I was good right up to "within functions...". I use super globals
within functions all the time.

..oO(Sanders Kaufman)

>Michael Fesser wrote:
>
>> | Please note that variable variables cannot be used with PHP's
>> | Superglobal arrays within functions or class methods.
>
>I read that, and re-read it, and re-read it... and I can't figure out
>what it means. Can you re-phrase it?
>
>I was good right up to "within functions...". I use super globals
>within functions all the time.

A variable variable is something like that:

$foo = 'bar';
$bar = 42;

print ${$foo}; // prints 42

This means the name of the variable is taken from another (string)
variable. The same can be done with superglobals, but not if you're
inside a function or method:

function test() {
$foo = '_GET';
var_dump(${$foo}); // throws a notice
}

Micha

Michael Fesser wrote:

> A variable variable is something like that:
>
> $foo = 'bar';
> $bar = 42;
>
> print ${$foo}; // prints 42
>
> This means the name of the variable is taken from another (string)
> variable. The same can be done with superglobals, but not if you're
> inside a function or method:
>
> function test() {
> $foo = '_GET';
> var_dump(${$foo}); // throws a notice
> }

I think that what's confusing me is that double-dollar thing.
I've seen it before, but thought it was a typo.

Could you tell me what it means, or where to look in the docs to find
out about it.