Hi,

I have a +200 kb log file from which I want to remove lines such as this
one:

5950K ......... ......... ......... ......... ......... ......... 59%
5600K ......... ......... ......... ......... ......... ......... 60%
5650K ......... ......... ......... ......... ......... ......... 61%

It's called wget-log. I'm not really good at linux bash shells so how do
I remove those lines with "......... ......... ......... ........." ?

I suppose I could do something like "cat wget-log |
(some-command/grep?) > newfile" but there are probably better methods,
including not creating a new file...


Best regards
Martin Jørgensen

--
---------------------------------------------------------------------------
Home of Martin Jørgensen - http://www.martinjoergensen.dk

sed -i "/......... ......... ......... ......... ......... ......... /d"
urlog

"Martin Jørgensen" <hotmail_spam@hotmail.com>
??????:1k43s3-k95.ln1@news.tdc.dk...
> Hi,
>
> I have a +200 kb log file from which I want to remove lines such as this
> one:
>
> 5950K ......... ......... ......... ......... ......... ......... 59%
> 5600K ......... ......... ......... ......... ......... ......... 60%
> 5650K ......... ......... ......... ......... ......... ......... 61%
>
> It's called wget-log. I'm not really good at linux bash shells so how do
> I remove those lines with "......... ......... ......... ........." ?
>
> I suppose I could do something like "cat wget-log |
> (some-command/grep?) > newfile" but there are probably better methods,
> including not creating a new file...
>
>
> Best regards
> Martin Jørgensen
>
> --
> --------------------------------------------------------------------------
-
> Home of Martin Jørgensen - http://www.martinjoergensen.dk

sorry,

you need escape .

"yulangdong" <yulangdong@hotmail.com> дÈëÏûÏ¢ÐÂÎÅ
:44eef415$1@news.starhub.net.sg...
> sed -i "/......... ......... ......... ......... ......... ......... /d"
> urlog
>
> "Martin Jørgensen" <hotmail_spam@hotmail.com>
> ??????:1k43s3-k95.ln1@news.tdc.dk...
> > Hi,
> >
> > I have a +200 kb log file from which I want to remove lines such as this
> > one:
> >
> > 5950K ......... ......... ......... ......... ......... ......... 59%
> > 5600K ......... ......... ......... ......... ......... ......... 60%
> > 5650K ......... ......... ......... ......... ......... ......... 61%
> >
> > It's called wget-log. I'm not really good at linux bash shells so how do
> > I remove those lines with "......... ......... ......... ........." ?
> >
> > I suppose I could do something like "cat wget-log |
> > (some-command/grep?) > newfile" but there are probably better methods,
> > including not creating a new file...
> >
> >
> > Best regards
> > Martin Jørgensen
> >
> > --
>
> --------------------------------------------------------------------------
> -
> > Home of Martin Jørgensen - http://www.martinjoergensen.dk
>
>

yulangdong wrote:

> "Martin Jørgensen" <hotmail_spam@hotmail.com>
> ??????:1k43s3-k95.ln1@news.tdc.dk...
>
>>Hi,
>>
>>I have a +200 kb log file from which I want to remove lines such as this
>>one:
>>
>>5950K ......... ......... ......... ......... ......... ......... 59%
>>5600K ......... ......... ......... ......... ......... ......... 60%
>>5650K ......... ......... ......... ......... ......... ......... 61%
>>
>>It's called wget-log. I'm not really good at linux bash shells so how do
>>I remove those lines with "......... ......... ......... ........." ?
>>
>>I suppose I could do something like "cat wget-log |
>>(some-command/grep?) > newfile" but there are probably better methods,
>>including not creating a new file...
>>
>>
>>Best regards
>>Martin Jørgensen
>>
>>--
>>--------------------------------------------------------------------------
>
> -
>
>>Home of Martin Jørgensen - http://www.martinjoergensen.dk
>
> sed -i "/......... ......... ......... ......... ......... ......... /d"
> urlog
>

Top-posting fixed. Please don't top-post.

A "." matches any character. Escape it ("\.") if you want to
specifically only match a period.

You also don't need to explicitly list every character if your sed
supports RE intervals, e.g. to match 6 repetitions of 9
periods-then-a-space:

sed '/\(\.\{9\} \)\{6\}/d'

Regards,

Ed.

Ed Morton <morton@lsupcaemnt.com> writes:

> yulangdong wrote:
>

>> sed -i "/......... ......... ......... ......... ......... ......... /d"
>> urlog

That worked fine, thanks.

> Top-posting fixed. Please don't top-post.
>
> A "." matches any character. Escape it ("\.") if you want to
> specifically only match a period.

Only escape the first character, right? Or every one? I also don't
really understand whether or not the citation marks " " are necessary?

> You also don't need to explicitly list every character if your sed
> supports RE intervals, e.g. to match 6 repetitions of 9
> periods-then-a-space:
>
> sed '/\(\.\{9\} \)\{6\}/d'

That's too advanced for me... Can you break it up and explain that to me?


Best regards
Martin Jørgensen

--
---------------------------------------------------------------------------
Home of Martin Jørgensen - http://www.martinjoergensen.dk

I would recommend learning perl and regular expressions. Try using the
following script:

Script Name: unclog.pl (or whatever you want to call it)
=======================
#!/usr/bin/perl -wn

print if (!/^.*\.{9} .*$/);

Make sure the permissions on unclog.pl are set to execute (i.e. 770)

Then run the script as follows:

unclog.pl wget-log > wget-unclog

Hope this s.

Art Ramos

Martin Jørgensen wrote:
> Hi,
>
> I have a +200 kb log file from which I want to remove lines such as this
> one:
>
> 5950K ......... ......... ......... ......... ......... ......... 59%
> 5600K ......... ......... ......... ......... ......... ......... 60%
> 5650K ......... ......... ......... ......... ......... ......... 61%
>
> It's called wget-log. I'm not really good at linux bash shells so how do
> I remove those lines with "......... ......... ......... ........." ?
>
> I suppose I could do something like "cat wget-log |
> (some-command/grep?) > newfile" but there are probably better methods,
> including not creating a new file...
>
>
> Best regards
> Martin Jørgensen
>
> --
> ---------------------------------------------------------------------------
> Home of Martin Jørgensen - http://www.martinjoergensen.dk

First Lensman wrote:
> I would recommend learning perl and regular expressions. Try using the
> following script:
>
> Script Name: unclog.pl (or whatever you want to call it)
> =======================
> #!/usr/bin/perl -wn
>
> print if (!/^.*\.{9} .*$/);
>
> Make sure the permissions on unclog.pl are set to execute (i.e. 770)
>
> Then run the script as follows:
>
> unclog.pl wget-log > wget-unclog
>

why not issue it directly on the command line:

perl -ne 'print if not /(??:\.){9} ){6}/' wget-log > wget-unclog

Xicheng

Martin Jørgensen wrote:
> Hi,
>
> I have a +200 kb log file from which I want to remove lines such as this
> one:
>
> 5950K ......... ......... ......... ......... ......... ......... 59%
> 5600K ......... ......... ......... ......... ......... ......... 60%
> 5650K ......... ......... ......... ......... ......... ......... 61%
>
> It's called wget-log. I'm not really good at linux bash shells so how do
> I remove those lines with "......... ......... ......... ........." ?
>
> I suppose I could do something like "cat wget-log |
> (some-command/grep?) > newfile" but there are probably better methods,
> including not creating a new file...
>
>
> Best regards
> Martin Jørgensen
>
> --
> ---------------------------------------------------------------------------
> Home of Martin Jørgensen - http://www.martinjoergensen.dk


if you know Python,

o = open("newfile","a")
for lines in open("wget-log"):
if not "......... ......... ......... ........." in lines:
o.write(lines)
o.close()