In Shell script, how do I check if a variable contains a :?, there is
something like variable =~ : in Perl, what about in Perl?

On 24 Aug 2006 11:06:27 -0700, yuetwah2000@hotmail.com
<yuetwah2000@hotmail.com> wrote:
> In Shell script, how do I check if a variable contains a :?, there is
> something like variable =~ : in Perl, what about in Perl?
>

case $variable in
*:\?*) echo yes ;;
*) echo no ;;
esac


--
The major sin is the sin of being born.
-- Samuel Beckett

On 2006-08-24, yuetwah2000@hotmail.com wrote:
> In Shell script, how do I check if a variable contains a :?, there is
> something like variable =~ : in Perl, what about in Perl?

Use case with filename patterns:

case $var in
*:*) echo "\$var contains :" ;;
*) echo "\$var does not contain :" ;;
esac


--
Chris F.A. Johnson, author <http://cfaj.freeshell.org>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence

On 24 Aug 2006 11:06:27 -0700, yuetwah2000@hotmail.com wrote:
> In Shell script, how do I check if a variable contains a :?, there is
> something like variable =~ : in Perl, what about in Perl?

If you want to do perl RE matching, simply do

var=FOObar
RE='(?i:foo)bar'

if perl -e 'exit 1 unless shift =~ shift' "$var" "$RE"
then printf '%s matches %s\n"
else echo "doesn't match"
fi

--
Stephane