> $db_server = "localhost";
> $db_user = "smith_admin";
> $db_pass = "password";
> $db_name = "smith_website";
> $db_table = "blog_category";
> $db_table1 = "blog_entry";
> $db_table2 = "quotes";
> $db_table3 = "ab_category";
> $db_table4 = "ab_person";
>
> $connect = mysql_connect($db_server, $db_user, $db_pass) OR DIE ('I
> can not connect to server because: ' .mysql_errno(). " -
> " .mysql_error());
> mysql_select_db($db_name, $connect) OR DIE ('I can not connect to
> server because: ' .mysql_errno(). " - " .mysql_error());

Ahh yes my fault never noticed that.

The problem you have is similar to the $connect problem, the tables being
defined outside of the function, you will need to also pass them as a
parameter

On Jun 24, 7:02 pm, "peter" <sub...@flexiwebhost.com> wrote:
> > $db_server = "localhost";
> > $db_user = "smith_admin";
> > $db_pass = "password";
> > $db_name = "smith_website";
> > $db_table = "blog_category";
> > $db_table1 = "blog_entry";
> > $db_table2 = "quotes";
> > $db_table3 = "ab_category";
> > $db_table4 = "ab_person";
>
> > $connect = mysql_connect($db_server, $db_user, $db_pass) OR DIE ('I
> > can not connect to server because: ' .mysql_errno(). " -
> > " .mysql_error());
> > mysql_select_db($db_name, $connect) OR DIE ('I can not connect to
> > server because: ' .mysql_errno(). " - " .mysql_error());
>
> Ahh yes my fault never noticed that.
>
> The problem you have is similar to the $connect problem, the tables being
> defined outside of the function, you will need to also pass them as a
> parameter

my gratitude forever that fixed it