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| alt.apache.configuration Apache web server configuration issues. |
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#1 |
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Messages: n/a
Hébergeur: |
Hi,
Without root access, is there an easy way to tell if the Linux server I am using is running Apache as Worker or Prefork? Failing that, with root access, how would I tell? Many thanks in advance, Jane |
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#2 |
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Messages: n/a
Hébergeur: |
Jane,
I'm not sure of the specifics for Linux, but this is how you would tell for Solaris, and I assume the methods would be very similar: Under the apache root directory, in this case, /u01/app/apache, cd to the "build" directory and cat the "config.nice" file. This file contains the options that were used during configure, for example: ---------------------------------------------- % cat config.nice #! /bin/sh # # Created by configure "./configure" \ "--prefix=/u01/app/apache" \ "--disable-ipv6" \ "--enable-so" \ "--enable-rewrite" \ "--enable-proxy" \ "--with-mpm=worker" \ "$@" ---------------------------------------------- in this case, apache was compiled with worker. another way would be, under the apache root dir, cd to bin: % ./httpd -l Compiled in modules: core.c mod_authn_file.c mod_authn_default.c mod_authz_host.c mod_authz_groupfile.c mod_authz_user.c mod_authz_default.c mod_auth_basic.c mod_include.c mod_filter.c mod_log_config.c mod_env.c mod_setenvif.c mod_proxy.c mod_proxy_connect.c mod_proxy_ftp.c mod_proxy_http.c mod_proxy_ajp.c mod_proxy_balancer.c worker.c http_core.c mod_mime.c mod_status.c mod_autoindex.c mod_asis.c mod_cgid.c mod_negotiation.c mod_dir.c mod_actions.c mod_userdir.c mod_alias.c mod_rewrite.c mod_so.c shows that worker was compiled into apache. You might also find some useful info here: http://www.camelrichard.org/apache-prefork-vs-worker Hope that s. kyle.reynolds@camelrichard.org On 17 May 2007 19:18:08 -0700, janedunnie@gmail.com wrote: >Hi, > >Without root access, is there an easy way to tell if the Linux server >I am using is running Apache as Worker or Prefork? > >Failing that, with root access, how would I tell? > >Many thanks in advance, >Jane |
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