Please forgive me, I have an obvious error. No response is needed from the
newsgroup.

"Joe Hesse" <joe_hesse@actcx.com> wrote in message
news:13lgau67k1b9c6c@corp.supernews.com...
> Hi,
>
> I have a template class and I want to define an operator << as a friend
> function. For each instantiation of the class I want a corresponding
> instantiation of operator <<.
> The following example fails to compile with g++ version 4.1.2.
> I would appreciate it if you could me fix it or point me to a
> suitable reference.
>
> Thank you,
> Joe Hesse
>
> ********************************************
> #include <iostream>
>
> // forward declaration
> template <typename T>
> class Foo;
>
> // forward declaration
> template <typename T>
> std:stream & operator << (std:stream &, const Foo<T> &);
>
> template <typename T>
> class Foo {
> private:
> T value;
> public:
> Foo(const T & v) : value(v) {}
> friend std:stream & operator << <> (std:stream &, const Foo<T> &);
> };
>
> // implement operator <<
> template <typename T>
> std:stream & operator << (std:stream &o, const Foo<T> &f) {
> return o << f.value ;
> }
>
> int main() {
> Foo<int> fi;
> std::cout << fi;
>
> return 0;
> }
>
> /* Here are the compiler error messages
> Test.cpp: In function int main():
> Test.cpp:26: error: no matching function for call to Foo<int>::Foo()
> Test.cpp:16: note: candidates are: Foo<T>::Foo(const T&) [with T = int]
> Test.cpp:12: note: Foo<int>::Foo(const Foo<int>&)
> */
>
> ********************************************
>