Discussion: Problems with Elseif
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Vieux 18/10/2007, 15h44   #1
Alec
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Par défaut Problems with Elseif

What am I doing wrong with this elseif condition?

$query = "SELECT company, priority FROM companyid_uks49179 WHERE
town='Bury St. Edmunds' AND category='sleep' AND priority IN
('1', '2', '3') ORDER BY priority";

This returns a result set of a number of companies with different
priority numbers from 1 to 3. see webpage http://www.freeweekends.co.uk/test3.php

I now want to create a table result for each one, with an 'elseif'
statement creating a different effect for each of the three different
priorities.

$result = mysql_query($query) or die ('Error in query: $query. ' .
mysql_error());

echo '<table border=1 cellpadding=10>';

while($row = mysql_fetch_object($result))

{
$priority = $row['priority'];

if ($priority == '1')

{
echo '<tr>';
echo "<td>$row->company</td>";
echo '<tr>';
echo "<td>test1</td>";
echo '<tr>';
}

elseif ($priority == '2')

{
echo '<tr>';
echo "<td>$row->company</td>";
echo '<tr>';
echo "<td>test2</td>";
echo '<tr>';
}

else

{
echo '<tr>';
echo "<td>$row->company</td>";
echo '<tr>';
echo "<td>test3</td>";
echo '<tr>';
}

}
echo '</table>';

This returns all the results as if they were not priority 1 or 2. See
http://www.freeweekends.co.uk/test2.php

Beginners question I know, but what am I doing wrong???

Many thanks

Alec

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