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Vieux 28/08/2007, 18h34   #6
Weston, Craig \
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Par défaut RE: [MYSQL]Time formatting for cycle time.

Ok, So, What I have come up with (so far) as a variant of Baron's query:



SET @d1 = '2007-2-1 00:00:00';# Start date
SET @d2 = '2007-2-28 23:59:59';# End date
SET @tdiff = TIMEDIFF( TIME(@d1), TIME(@d2) );
SET @dow1 = DAYOFWEEK(@d1);
SET @dow2 = DAYOFWEEK(@d2);
SET @days = DATEDIFF(@d2,@d1);
SET @wknddays = 2 * FLOOR( @days / 7 ) +
IF( @dow1 = 1 AND @dow2 > 1, 1,
IF( @dow1 = 7 AND @dow2 = 1, 1,
IF( @dow1 > 1 AND @dow1 > @dow2, 2,
IF( @dow1 < 7 AND @dow2 = 7, 1, 0 )
)
)
);
SET @days2 = FLOOR(@days - @wkndDays) - (IF( @tdiff > 0, 1, 0 ) +
(SELECT count(*) FROM `resource_data`.`holidays` WHERE
`resource_data`.`holidays`.`date` BETWEEN @d1 AND @d2));
SET @tdiff = IF( ASCII(@tdiff) = 45, SUBSTRING(@tdiff,2), TIMEDIFF(
'24:00:00', @tdiff ));
SELECT CONCAT( @days2, ' days ', @tdiff ),
@wknddays,
@days,
@days2,
@tdiff,
IF( @tdiff < 0, 1, 0 ),#Test value 1
IF( @tdiff > 0, 1, 0 ),#Test value 2
FLOOR(@days - @wkndDays),
(SELECT count(*) FROM `holidays` WHERE `holidays`.`date` BETWEEN @d1
AND @d2);



What I did was reverse the @tdiff equation to add a day for a positive
@tdiff instead of subtracting it. My test month, February, has 2
holidays in it.

The results:

+------------------------------------+-----------+-------+
| CONCAT( @days2, ' days ', @tdiff ) | @wknddays | @days |
+------------------------------------+-----------+-------+
| 17 days 23:59:59 | 8 | 27 |
+------------------------------------+-----------+-------+


--------+------------------------+------------------------+----------+
@days2 | IF( @tdiff < 0, 1, 0 ) | IF( @tdiff > 0, 1, 0 ) | holidays |
--------+------------------------+------------------------+----------+
17 | 0 | 1 | 2 |
--------+------------------------+------------------------+----------+

This seems to account for the remainder better?

Of course the original reason it was added was to take into account
times that were earlier, which it does not seem to do?

Thank you for your !
Craig
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