On Sep 19, 12:35 am, sysop...@gmail.com wrote:
> On Sep 18, 3:50 pm, kj <kils...@gmail.com> wrote:
>
>
>
> > I searched around as much as I could for this, let me know if anyone
> > has some advice. I would like to actually output the name of the
> > variable instead of the value.
>
> > <snip>
> > $requiredInt=array($amnt,$bNum,$rNum,$oNum,$numPay ments);
> > $i=0;
>
> > foreach ($requiredInt as $key => $val) {
> > if (!filter_var($val, FILTER_VALIDATE_INT)) { echo('Item: '.!Output
> > the variable name here!.' is required and must be a numeric integer,
> > please go back and make this correction before submitting.<br />'); }
> > $i++;}
>
> > unset($requiredInt);
> > </snip>
>
> > Any advice is appreciated. Thank you.
> > garrett
>
> I'm not certain what you're asking, but I think you want to take
> $foo='bar' and get 'foo' out of it, which I'm almost certain can't be
> done. The easiest way to get around your problem is to set the key of
> each item equal to the name:
> $requiredInt=array('amnt'=>$amnt,'bNum'=>$bNum,'rN um'=>$rNum,'oNum'=>
> $oNum,'numPayments'=>$numPayments);
>
> Alternatively, if you want to avoid the repetition, you can just set
> the array to the string names:
> $requiredInt=array('amnt','bNum','rNum','oNum','nu mPayments');
>
> Then in the foreach you can use $val to get the name of the variable
> and $$val to get its value.

Your assumption about what I tried to do was right. I tried your
second solution, to avoid the repetition. It works perfectly and
solved my issue. Thank you very much!