"Doug Ritschel" <ritschel@optonline.net> writes:

> i=0
> echo "this is a test" | while read line; do
> i = `expr $i + 1`
> done
> echo $i

The while loop is run in a subshell and it has it's own local
variables so changing them won't change the value of oryginal
variable.

In fact AFAIK the question was answered in FAQ.


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