That did it!

I love the simple solutions, thank you very much for the solution and
the speedy reply :-)

-Mats

Chris F.A. Johnson wrote:
> On 2006-08-25, mats.karstad@gmail.com wrote:
> > Hi,
> >
> > I am pretty new to shell scripting so this problem might be trivial,
> > but I can't for the life of me figure it out or find any resources
> > online that does what I want.
> >
> > Basically I am grepping from a large log file as I am only interested
> > in certain entries.
> >
> > The code I am using is the following:
> >
> > MAILBODY=`grep -n "XX" ${LOGFILE}`
> > SUBJECT="Logg informasjon"
> >
> > if [ "$MAILBODY" != '' ] ; then
> >
> > echo $MAILBODY | ${MAILPROGRAM} -s "${SUBJECT}" ${MOTTAKER}
> > fi
> >
> > Just basically grepping the line with token XX then if data was found i
> > send this via email.
> >
> > My problem is first of all, I do not want the token to be printed (not
> > critical) secondly and most importantly I want each entry to be printed
> > on separate lines as in adding a line break at the end of each result,
> > because as it is it just tags all the lines after each other making it
> > hopeless to use.
>
> Quote your variable:
>
> echo "$MAILBODY" | ${MAILPROGRAM} -s "${SUBJECT}" ${MOTTAKER}
>
>
> --
> Chris F.A. Johnson, author <http://cfaj.freeshell.org>
> Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
> ===== My code in this post, if any, assumes the POSIX locale
> ===== and is released under the GNU General Public Licence