Stephan 'smg' Grein wrote:
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> phillip.s.powell@gmail.com wrote:
> > # NOW WE COPY EVERYTHING OVER TO THE NEW FOLDERS IN $csvBackupPath
> > cp -pr "$clientDocPath/*.csv" "$csvBackupPath/clientCSV"
> > cp -pr "$projectDocPath/*.csv" "$csvBackupPath/projectCSV"
> >
> Try that:
> cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
> "$csvBackupPath/clientCSV/${file}"; done
> cd "$projectDocPath/" && for file in *.csv; do cp -p "$file"
> "$csvBackupPath/projectCSV/${file}"; done

you may get into trouble if "$projectDocPath" is not an absolute path.
to keep the current directory info, you may want to use sub-shell with
your commands, like

( cd "$clientDocPath/" && for file in *.csv; do cp -p "$file"
"$csvBackupPath/clientCSV/${file}"; done )

Also, using 'find' might save OP some typing:

find "$clientDocPath" -type f -name "*.csv"
-exec cp -p "{}" "$csvBackupPath/clientCSV/" \;

or use find | xargs, find -exec ... + .....

(untested)
Xicheng