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24/08/2006, 16h08

On 24 Aug 2006 07:11:52 -0700, pedromalves@gmail.com
<pedromalves@gmail.com> wrote:
> I'm trying to do search/replace on multiple text files.
> I'm using the following script:
>
> #!/bin/sh
> USAGE=`basename $0`
> USAGE=$USAGE' <PATTERN> <SUBSTITUTE> <FILES PATH>'
> if test $# -lt 3
> then
> echo "-I-: $USAGE"
> exit 1
> fi
> PATTERN=$1
PATTERN="$1"
> shift
> SUBSTITUTION=$1
SUBSTITUTION="$1"
> shift
> for i;
> do
> mv $i $i.old;
mv "$i" "$i.old"
> sed -e 's/$PATTERN/$SUBSTITUTION/g' $i.old > $i;
> done
> \rm *.old
>
> What happens is that if I echo the commands out to the shell and
> execute them, the replacement will occur as expect. If I run to script
> to execute the sed command, the resulting output will not have any
> change.
>
> Can someone please me understand this?
>
Variables are not substituted inside single quotes!
sed -e "s/$PATTERN/$SUBSTITUTION/g" $i.old > $i;

24/08/2006, 16h08	#2
Bill Marcum Messages: n/a Hébergeur:	Re: Sed Find and Replace Multiple Files On 24 Aug 2006 07:11:52 -0700, pedromalves@gmail.com <pedromalves@gmail.com> wrote: > I'm trying to do search/replace on multiple text files. > I'm using the following script: > > #!/bin/sh > USAGE=`basename $0` > USAGE=$USAGE' <PATTERN> <SUBSTITUTE> <FILES PATH>' > if test $# -lt 3 > then > echo "-I-: $USAGE" > exit 1 > fi > PATTERN=$1 PATTERN="$1" > shift > SUBSTITUTION=$1 SUBSTITUTION="$1" > shift > for i; > do > mv $i $i.old; mv "$i" "$i.old" > sed -e 's/$PATTERN/$SUBSTITUTION/g' $i.old > $i; > done > \rm *.old > > What happens is that if I echo the commands out to the shell and > execute them, the replacement will occur as expect. If I run to script > to execute the sed command, the resulting output will not have any > change. > > Can someone please me understand this? > Variables are not substituted inside single quotes! sed -e "s/$PATTERN/$SUBSTITUTION/g" $i.old > $i;