PHWinfo - Afficher un message - bash: process substitution not working in script

29/04/2008, 21h50

On Tuesday 29 April 2008 21:47, lihao0129@gmail.com wrote:

>> Does your script begin with #!/bin/bash?
>
> Thanks, if I change the shebang line from
>
> #!/bin/sh
>
> to
>
> #!/bin/bash
>
> my original script worked. Just curious since 'ls -l /bin/sh' shows
>
> lrwxrwxrwx 1 root root 4 Apr 23 15:20 /bin/sh -> bash

But bash behaves slightly differently if it's invoked with the name "sh". It
actually (tries to) run in POSIX mode, where the <(..) construct does not
exist. See the man for the details.

--
All the commands are tested with bash and GNU tools, so they may use
nonstandard features. I try to mention when something is nonstandard (if
I'm aware of that), but I may miss something. Corrections are welcome.

29/04/2008, 21h50	#7
pk Messages: n/a Hébergeur:	Re: bash: process substitution not working in script On Tuesday 29 April 2008 21:47, lihao0129@gmail.com wrote: >> Does your script begin with #!/bin/bash? > > Thanks, if I change the shebang line from > > #!/bin/sh > > to > > #!/bin/bash > > my original script worked. Just curious since 'ls -l /bin/sh' shows > > lrwxrwxrwx 1 root root 4 Apr 23 15:20 /bin/sh -> bash But bash behaves slightly differently if it's invoked with the name "sh". It actually (tries to) run in POSIX mode, where the <(..) construct does not exist. See the man for the details. -- All the commands are tested with bash and GNU tools, so they may use nonstandard features. I try to mention when something is nonstandard (if I'm aware of that), but I may miss something. Corrections are welcome.