Re: Class Template with Specialization code Giving Error
On Feb 21, 4:41 pm, Reetesh Mukul <reetesh.mu...@gmail.com> wrote:
> On Feb 21, 4:36 pm, Pallav singh <singh.pal...@gmail.com> wrote:
>
> > On Feb 21, 4:26 pm, Reetesh Mukul <reetesh.mu...@gmail.com> wrote:
>
> > > On Feb 21, 3:55 pm, Pallav singh <singh.pal...@gmail.com> wrote:> Hi
>
> > > > I am getting error in compiling this code .......Unable to find error
> > > > Kindly suggest me something.
>
> > > > Thanks
> > > > Pallav
>
> > > > ================================================== =================
>
> > > > #include<iostream.h>
>
> > > You should use <iostream> in place of iostream.h. For cout, you can
> > > use
> > > using std::cout;
>
> > > > template<typename T>
> > > > class B
> > > > {
> > > > public :
>
> > > > T DependentName;
> > > > int basefield;
> > > > typedef int X;
>
> > > > };
>
> > > > template<>
> > > > class B<char>
> > > > {
>
> > > > public :
> > > > enum E{basefield = 1};
> > > > int func()
> > > > { return basefield;}
>
> > > > };
>
> > > > template<typename T>
> > > > class D:B<T>
> > > > {
> > > > public :
> > > > int func()
> > > > { basefield = 12;
>
> > > Two errors in this step (when instantiation of D<char> is done):-
> > > 1)C++ does not permit implicit conversion from int type to enum type.
> > > That is you cannot write
> > > enum R{A,B};
> > > R x = 1;
>
> > > 2)basefield is an l-value, that is it is an integral constant, a
> > > lvalue. So you cannot assign
> > > any thing to it.
>
> > > > return basefield; }
>
> > > > };
>
> > > > void call(D<int> & obj_int){
> > > > cout<<"called function :: call(B<int> & obj_int) ::
> > > > "<<obj_int.func()<<endl;}
>
> > > > void call(D<char> & obj_char){
> > > > cout<<"called function :: call(B<char> & obj_char)::
> > > > "<<obj_char.func()<<endl;}
>
> > > > int main()
> > > > {
>
> > > > D<char> obj_char;
> > > > D<int> obj_int;
>
> > > > call(obj_char);
> > > > call(obj_int);
>
> > > > return 0;
>
> > > > }
>
> > > Regards,
> > > Reetesh Mukul
>
> > ---------------------------------------------------------------------------------
>
> > Hi
>
> > as my knowledge with char ...it should look to Base class Specialized
> > function
> > where i am Not doing any assignment but access
>
> The what about the assignment in D<char>::func() ...
> basefield = 1;
>
>
>
> > while it should call generalized Base class for Other cases where i
> > did assigment
>
> > Thanks
> > Pallav
>
> I am not able to get your point, can you explain.
>
> Regards,
> Reetesh Mukul
--------------------------------------------------------------------------
thats beauty of Specialization when i call B<char> it will call
specialized base class for char
Variable / functionality of specialized class has No relation with
Generalized Base Class
when i call B<int> , B<bool> ---------It call generalized Base Class
while when i call B<char> ----------- It should call my Specialized
Base Class
U can see Above in the Code ........ I Have written two class B
Thanks
pallav
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